/vt/ - Virtual Youtubers

>>7872670
I have created a mathematical formula in response. Please let me know if it is adequate.
>d is number of males involved in a sexual encounter (where a male is a biological male born with a penis)
>p is number of participants in a sexual encounter (doesn't matter how they identify, value d fixes that issue)
>g is the gayness factor, which is an absolute value
>The gayness factor is the degree of deviation from heteronormativity (0). It is the expressed as picrel:
>|g| = ((-dp)+2)/p
>(2 is the number of genders aka the gender binary)
>if g is greater than 0, then it's gay

For example. One dick, 2 people (d=1, p=2).
>|g| = ((-1*2)+2)/2
>|g| = (-2+2)/2
>|g| = 0/2
>g=0
G is zero, so a sexual encounter with 2 people, where only one of them has a dick is straight.

Now let's say there are 2 women involved in a sexual encounter. So d=0, p=2. Let's solve for the gayness factor.
>|g| = ((-0*2)+2)/2
>|g| = (0+2)/2
>|g| = 2/2
>g = 1
>1 is greater than 0, so it's kinda gay

Now let's say we have two nice boys exploring one another's bodies in a sexual way. So d=2, p=2
>|g| = ((-2*2)+2)/2
>|g| = (-4+2)/2
>|g| = -2/2
>|g| =-1
>g=1
1 is also greater than zero, so it's kinda gay.

Now let's say we're in ram ranch. So d=36, p=36. Let's solve for the gayness.
>|g| = ((-36*36)+2)/36
>|g| = (-1296+2)/36
>|g| = -1294/36
>|g| = -35.94
>g = 35.94
>36 is greater than 0, so it's quite gay

This formula can only apply with masturbation if you remove the masturbatee from the equation. Thanks for listening to my tedtalk.