/sci/ - Science & Math

How do I into beam hardening correction?
I need to image something with a much lower density gradient than the metal that's fucking my image up.
Should I use a higher KV to try and mitigate the beam hardening then correct with enhancement at the risk of losing my tissue resolution or should I use low kV and use high beam hardening post-processing correction.
The problem I've been having is in between the metal, I lose all resolution because the beam hardening artifacts are so pervasive it makes the image worthless

are rhibosomes seriously a bunch of blue dyed spaghetti? is this why people ares inherently autistic?

>>5942332

He is sane as a Deacon.

>>5435456
I'm looking for actual research, not speculation, propaganda and/or stupidity

People go to /pol/ with an agenda,
People come to /sci/ with evidence and research

Research on the effectiveness or otherwise of suicide protests for social/political change? ANYONE got any goss on it?

>>5417077

Reported to the National Security Administration for asking for information on how to construct a nuclear weapon.

>>5083851
he said "WANING". you know? when the moon looks like a crescent? i think he also meant "their" as in the two pictures. but one of them is the moon and the other looks like a picture of Venus. and yes the moon has moved from its position, because the moons orbit is always a little different each time it goes around. >>5083792
if your this stupid, get off /sci/ and kill yourself otherwise, stop trolling.

>>5031340
this friend got it. yes this was my homework and yes we all know OP is faggot, but i was testing to see just how smart /sci/ really is. not to troll but to see how accurate you really are. four posts. congradulations

answer the question. find T. a passenger trains speed is 60 mi/h. a frieght trains speed is 40 mi/h. the passengers train travels the same distance in 1.5 h less time than the freight train. how long does each train take to make the trip?

report your answers.
pic unrelated

I need all the information anyone can give me, no matter how small it is. thanks for the answers. to be honest, I didn't think I would get a straight answer from anyone.

>>5017655
of course, but cleverbot isnt very clever. if anything random. I know that if i get it fresh, its not going to be smart. thats why im going to teach it.

>>5017620
its not stupid. cleverbot is basically the same thing. i just want to find a source code. kind of like a clean cleverbot that doesn't know any responses

Hi /sci/, I need help. im sure there are alot of smart people lurking on this board. so I need your help making a program in java. I want to create an Artificial Intelligence to teach. yes It sounds similar to cleverbot, but i want it different. I want to teach it the responses. I want it to learn. sort of like teaching a child from a fresh start. can anyone code this, or at least direct me to a program or java that does this already. it would be greatly appreciated.

Heck, I remember seeing this on wikipedia.

>>4757264
Uh, a "good" Calc II textbook doesn't really exist.

As a free resource, Gilbert Strang's Calculus book on OCW can be used for Calc II material -- in particular, chapters 6 through 10.

>>4755340
ABE = 90-x/2
Complement of ABE = 90-ABE = 90-(90-x/2) = x/2

First, draw a line connecting D and E.

Now, using the Secant-Secant Power Theorem (a corollary of the power of a point theorem: http://en.wikipedia.org/wiki/Power_of_a_point#Theorems)), we can say FB*DB = GB*EB. This implies DB/EB = GB/FB. Taking angle FBG into account, it's clear that triangle DBE is similar to triangle GBF. This implies that angle BDE is equal to angle BGF.

Now, it is enough to prove that angle BGF and the angle enclosed by the line EB and the right green line (going down) are equal.

Draw the radii AB and AE.

Let the angle EAB be equal to x. Then angles AEB and ABE both equal 90-x/2 because their sum must equal 180-x and the triangle contained by the radii and the chord is isosceles, implying the angles must be equal. Therefore complement to angle ABE (that is, the angle contained by line BE and the lower right green line segment ) is x/2.

So the complementary angle is half of angle EAB. And by the inscribed angle theorem, angle EDB is equal to half of angle EAB. And by our work above, angle EDB is equal to BGF. So BGF is equal to the complementary angle. Since the opposite interior angles are equal, the green lines must be parallel.

>>4755162
Hahaha, solution incoming.

I'll be using >>4754965's picture as a reference.

Oh, you're going to feel so silly when I post the solution...

In most areas of math, there are major "objects" that are studied. In calculus/real analysis, it's the real numbers and functions. In number theory, it's the integers/natural numbers. In complex analysis, it's holomorphic functions. You should be able to at least say what object you're studying, even if you don't know enough to say exactly what it does.

>>4754967
No, I actually know how to do this problem. The solution involves something most of you have probably forgotten.

It's "Putnam-level" in the sense that if you don't know how to solve this, even some of the AMC/AIME/USAMO problems will appear impossible to you.

>mfw /sci/ can't do a simple geometry problem

Can /sci/ solve the following question?

Given two intersecting circles of unequal radius, take a point on the smaller circle and draw one line that intersects one of the circles' points of intersection and then draw another line to intersect the other point of intersection. (in my diagram, these lines are red)

These two lines then intersect the bigger circle at two other places; draw a line connecting those two points. (This is the lower green line in my diagram.)

Now, go back to the smaller circle, and from the point on the smaller circle where the two red lines intersect, draw the circle's tangent line. (This is the upper green line in my diagram)

Prove that the green lines are parallel.

>>3964094

Right...the imperial system is intuitive to you...because you grew up in a country which uses the imperial system.

But what's your point?

Objectively, SI is far superior to the imperial system, and how could one possibly benefit from working with two entirely different measurement systems?

>>3963834

...what corporations?