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/sci/ - Science & Math

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>> No.15739787 [View]

>>15737698
Any decent Calculus book, regardless of language, is pure pain without first understanding HS math.
You can either go back to HS stuff, do it and then try calculus again or you can maintain your current strategy. You will progress either way, so pick the route you prefer.

>> No.15739760 [View]

>>15739732
I've been on my way since 2018 when I got off my ass and started the Gelfand babby-tier sequence that was being shilled back then, only got to the middle of Munkres so far and am currently distracted by Brouwer's philosophy book and bits of googology. Would be faster but I dropped out of high school and work full time. Hoping to be able to comprehend the videos of the youtuber who tried to tackle IUTT by the end of 2027 if either youtube or archive.org (I archived them) are still around by then.

>> No.15710806 [View]

The sticky:
https://web.archive.org/web/20230000000000*/https://sites.google.com/site/scienceandmathguide/

Its earlier precursor:
https://web.archive.org/web/20230000000000*/https://sciguide.tk

>> No.15704753 [View]

https://openstax.org
free algebra textbooks

>> No.14825433 [View]

Gonna start finding the dumbest math homework problems on reddit and spamming them in /sqt/, if I see anything funny I'll post it here

>> No.14685245 [View]
File: 91 KB, 612x612, IMG-20181014-WA0004.jpg [View same] [iqdb] [saucenao] [google]
14685245

>Hidden threads: 143

>> No.14676434 [View]

Agree, 98% of users failed Algebra 1. I have been away from the board for a while, who is mandibaur?

>> No.12377714 [View]

>>12377707
New thread

>> No.12377707 [View]
File: 7 KB, 598x139, the-number-line.png [View same] [iqdb] [saucenao] [google]
12377707

Infinitely many coin tosses edition.
Preceding thread: >>12367198

Talk math, or even do math, if you aren't scared.

>> No.12274584 [View]

The memories...

>> No.12117170 [View]

Gases are made out of particles that, despite being restrained by gravity, have enough energy individually to fly around at high velocity geodesics in every direction.
When a temperature differential is present within the gas the collisions between the hotter and colder components will form current systems where the colder components are disproportionately pushed into slow moving high-density wavefronts.
In three dimensions with a preferred gravitational direction, these cold, low pressure areas will stick to low-altitude areas (like sea level) and hot, high pressure areas will flow around randomly at higher altitudes.
If hot air is trapped at a low altitude with cold air above it, it will push cold air out of the way vertically at wherever the cold air is thinnest, forming a spike-shaped updraft.
When you account for the Coriolis force, these updrafts will rotate as hot air is drained upwards like an upside down whirlpool.
The tropical region of the Atlantic is very hot compared to the air 3km above the tropical region of the Atlantic, so it's all of the above on a colossal scale.

>> No.11971945 [View]
File: 1.21 MB, 1521x2048, 6978755326_fad0f5c85e_k.jpg [View same] [iqdb] [saucenao] [google]
11971945

Lots of ppl ask why, but what about why not? Land is pretty great.

>> No.11919011 [View]
File: 26 KB, 676x352, EZN5WSNXQAAhGJT.png [View same] [iqdb] [saucenao] [google]
11919011

>Annual exam threads
>People can't into trigonometry after a whole year
Welcome to /sci/, YLYL.

>> No.11795526 [View]

>>11795524
(You)

>> No.11534472 [View]

>>11534445
I also have made this because it came up and I think it's helped:

Adding Time
Here is a nice simple way to add hours and minutes together:
Let's add 1 hr and 35 minutes and 3 hr 55 minutes together.
What you do is this:
make the 1 hr 35 minutes into one number, which will give us 135 and do the same for
the other number, 3 hours 55 minutes, giving us 355
Now you want to add these two numbers together:

135
355
____
490

So we now have a sub total of 490.
What you need to do to this and all sub totals is add the time constant of 40.
No matter what the hours and minutes are, just add the 40 time constant to the sub
total.
490 + 40 = 530
so we can now see our answer is 5 hrs and 30 minutes!

>> No.11534445 [View]
File: 146 KB, 786x455, it-came-from-the-deep.jpg [View same] [iqdb] [saucenao] [google]
11534445

I'm writing homework for somebody aged 9.
Does the following look good:

This technique teaches you how to multiply any number by eleven, easily and quickly.
We will take a few examples and from these you will see the pattern used and also how
easy they are to do.
So, to begin let’s try [math]12[/math] time [math]11[/math].
First things first you will ignore the [math]11[/math] for the moment and concentrate on the [math]12[/math].
Split the twelve apart, like so:
[math]1\;2[/math]
Add these two digits together [math]1\;+\;2\;=\;3[/math]
[math]1+2\;=\;3[/math]
Place the answer, [math]3[/math] in between the [math]12[/math] to give [math]132[/math]
[math]11\;X\;12\;=\;132[/math]
Let’s try another:
[math]48\;X\;11[/math]
again, leave the [math]11[/math] alone for a moment and work with the [math]48[/math]
[math]4\;+\;8\;=\;12[/math]
So now we have to put the [math]12[/math] in between the [math]4[/math] and [math]8[/math] but don’t do this:
[math]4128[/math] as that is wrong...
First, do this: Place the [math]2[/math] from the twelve in between the [math]4[/math] and [math]8[/math] giving [math]428[/math].
Now we need to input the [math]1[/math] from the twelve into our answer also, and to do this just add
the one from [math]12[/math] to the [math]4[/math] of [math]428[/math] giving [math]528[/math]!
Ok, one more
[math]74\;X\;11[/math]
[eqn]7+4\;=\;11[/eqn]
[math]7[/math] (put the [math]1[/math] from the right of [math]11[/math] in) and [math]4[/math]
then add the [math]1[/math] from the left of [math]11[/math] to the [math]7[/math]
[math]74\;X\;11\;=\;814[/math]
This is a really simple method and will save you so much time with your [math]11[/math]times tables.

>> No.11504426 [View]

You would really enjoy Don Hertzfeldt's three part animated movie "It's such a beautiful day". It's a comedy/drama/scifi about solipsism and aging

>> No.11504402 [View]

I remember a long time ago I posted why I thought it was A and was thoroughly corrected.
It's B for a very simple reason:
You can get infinite energy, momentum, whatever from nothing in any spatial region that isn't simply connected. No intuitions about conservation laws hold as soon as you throw out that topology.
Try visualising this from the cube's perspective. The orange portal is literally throwing a region of spacetime at the cube. It doesn't happen in the game but that's because they used cheap programming tricks to make Valve-tier coding work. There's a post on stackexchamge where somebody did code this into OpenRelativity and it was B, I'll dig it up.

>> No.11495275 [View]

>>11494729
>No rotifers

>> No.11494776 [View]

Math monk is not a meme, it really works.

>> No.11487635 [View]

>>11487632
And not just a vague fractally shape that resembles goatse, but actual goatse? Just by zooming so deep that the fractally bits get so small they vanish under the anti-aliasing?

>> No.11487632 [View]
File: 127 KB, 1280x720, maxresdefault.jpg [View same] [iqdb] [saucenao] [google]
11487632

>>11487613
I'm asking about the underlying distribution of escape time values in the complement to the M-set. Can you find, with a coloring algorithm that uses the full coloring space and a correct choice of zoom scale and position, every possible computer-displayable image in the mandelbrot set? Here they found two letters S in purple on a red background but with enough zoom (arbitrarily large but still finite) can you find any image? Can you find goatse?

>> No.11487615 [View]

>>11487604
You are observing light that intersects your position and making inferences about the path it took to get to you based on the qualities (proportions of wavelengths, angular differences) of that light. That's kinda how perception works, it's just dressed up enough to be mathematically rigorous.

>> No.11487606 [View]

If you color the points exterior to the mandelbrot set according to the modular number of iterations under the mandelbrot function the point takes before exceeding 2 with a coloring algorithm that uses the full color space a given monitor can display, can you display every possible combination of pixel colours that monitor can display?
It helps to think of pixels as arbitrary lattice points, but it's still a tough question. I can't even prove it for a 8-bit color space on a 2*2 monitor.

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