/sci/ - Science & Math

>>4732315
consider real numbers between 0 and 1

and square made of these same reals in two cordinates

bijection between 0.abcdefgh... and (0.aceg..., 0.bdfh...)

>>4729347
that's how we (t)roll

>>4729328
Fail. Bases can be negative.

>>4729330
f'(x) = -1 for x < 0
undefined for x = 0
f'(x) = 1 for x > 0

when converting it is better to put the centre of the ellipse at the origin, rather than one of the foci.

so a translation to the left should be your first step

48÷2(9+3)
24÷(9+3)
24/9 + 3
24/9 + 27/9
51/9
17/3

>>4729158
what's wrong with "snobbery". if you think all cultures are somehow as good as each other you are just a liberal relativist.

>>4729117
>can't name the current president of every country in the G8

girls laughing

>not making exhaustive lists of favourite music and films
>not being aspie

>>4729120
ok, the word you are looking for this object is "cuboid"

V = 3x^2h = 200

so h = 200/(3x^2)

A = 3x^2 + 3xh + xh = 3x^2 + 4xh

substitute h

A = 3x^2 + 800/(3x)

differentiate, set to zero, etc

what do you mean by "width"?

a picture is worth a thousand words, btw

>>4729104
nope, a water molecule is swallowed up

-CONH- and H20 = -COOH and NH2-

>>4729096
then just translate it upwards a unit

>>4729069
FP1?

I'll just do the induction step

<div class="math">\sum_{r=1}^{k+1}(r^{2}+1)r! = \sum_{r=1}^{k}(r^{2}+1)r!\; \: + \; ((k+1)^{2}+1)(k+1)!\; = \; k(k+1)!\; + \; ((k+1)^2+1)(k+1)!\; =\; (k^2 +3k+2)(k+1)!\; =\; (k+1)(k+2)(k+1)! = (k+1)(k+2)!</div>

>>4728009
also, the -1/4 is right, if you sub it into the original equation, not the mish mash you subbed it into

>>4727997
when you decide that |3x-8|=3x-8 realise this is only true if 3x-8>=0, but you got x = - 9 (you missed a negative) which makes 3x-8< 0, so you disallow -9

similar thing for |3x-8| = -3x + 8 only being true if 3x-8<=0

>>4727968
i know

it makes me cry

>>4727939
z is of form 6n + 4 by mod 7

>>4727939
z is of form 6n + 3 by mod 7

>>4727931
z is of form 4n+2 by mod 5