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/sci/ - Science & Math

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>> No.1749777 [View]
File: 26 KB, 399x372, reaction down retard.jpg [View same] [iqdb] [saucenao] [google]
1749777

>> No.1749724 [View]

/sci/ works fine for single books

>> No.1749525 [View]

For constant acceleration, <span class="math">v=at[/spoiler]. In your case, the velocity doesn't change from 0 to 1 second because acceleration is 0. After that, the particle accelerates with <span class="math">4\frac m{s^2}[/spoiler] for two seconds. Plug that into the equation above and there's your answer.

>> No.1749040 [View]
File: 8 KB, 235x261, cross out mass dr werner.jpg [View same] [iqdb] [saucenao] [google]
1749040

Hey, I've got an idea how to simplify the formula ...

>> No.1748815 [View]

If you can't contribute, you counteribute. In kindergarden you justle others, in school you steal their caps, and on the internet you post religion threads.

>> No.1748802 [View]

I assume sci doesn't give a crap. Maybe the highschoolers here do, you should address your question at them.

>> No.1748723 [View]

>>1748456
Fuck yeah residue theorem!

>> No.1745192 [View]

>>1745175
78312, that is, since a,b,c,d,e are assumed to be integers

>> No.1745175 [View]
File: 9 KB, 436x342, Unbenannt.png [View same] [iqdb] [saucenao] [google]
1745175

meh

>> No.1744199 [View]

That's not math, that's calculating.

>> No.1744191 [View]

>>1744173
Russel's teapot.
You don't have to explain shit. "You're dead wrong, shut up now please" is the kindest answer I can come up with.

>> No.1744150 [View]

Oh, and that image is not a covalent bond.

>> No.1744144 [View]

I'm pretty sure H2 is a purely covalent bond (at least under normal conditions).

>> No.1743946 [View]

Any polynom can be brought to the form
<div class="math">(x-\xi_1)(x-\xi_2)(x-\xi_3)\cdots</div>
where the <span class="math">\xi[/spoiler] are the roots, so in your case that's -1, 0, 2. Multiplying those parentheses out again yields the "normal" polynom form à la <span class="math">ax^2+bx+c[/spoiler].

Thus, your solution is the polynom
<div class="math">ax(x+1)(x-2</div>
a is still undetermined; the polynom above is every possible polynom of degree three that has the roots 0, -1, 2. If you know one additional point of the function, you've determined it uniquely.

>> No.1739708 [View]

>>1739673
Well, apart from the fact that you've chosen probably the worst example of English words in German when referring to the SpaceMaster program, you're probably right. Give it an English name and you can sell bottled piss here.

>> No.1739676 [View]

>>1739673
* Luleå University of Technology, Sweden (Coordinating University)
* University of Würzburg, Germany
* Cranfield University, England
* Czech Technical University, Czech Republic
* Helsinki University of Technology / Aalto University, Finland
* Université Paul Sabatier Toulouse III, France
* University of Tokyo, Japan
* Utah State University, U.S.A.

Yeah, stupid Germans!

>> No.1739663 [View]

>>1739657
Well, then I suggest you swallow your coffee before clicking the link
http://www.spacemaster.uni-wuerzburg.de/

>> No.1739647 [View]

One of my friends was asking to get the official title "master of the universe" instead of "space master", which is what it's currently called (master of space physics or something).

>> No.1739616 [View]

trololol

>> No.1739526 [View]

>>1739517
Particle physics invents internets, homeopaths puts stamps on stupid people. They should be equally supported for simplifying life for me.

>> No.1739495 [View]

>>1739489
Josef is defeated.
Back into your <span class="math">S^2[/spoiler] manifold, Josef!

>> No.1739461 [View]

>>1739441
Josef uses inverse angular momentum operator on his enemy! His degeneracy increased by 2.

>> No.1739412 [View]

>>1739404
You didn't hit because Joseph is spelt with f.
Josef uses identity operator on his enemy, because he's a fair fighter.

>> No.1739390 [View]

>>1739380
Josef uses gaussian wave packet! His group velocity increased!

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