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/sci/ - Science & Math

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9741077 No.9741077 [Reply] [Original]

is zero/zero undefined, zero, one or infinite?

>> No.9741087

>>9741077
yes

>> No.9741092
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9741092

There's only one absolute zero, and that is the universe before the big bang. Rest of zeros are only a meme. 0/0 = 0

>> No.9741129

>>9741077
Undefined.
Doesn't matter what's in the numerator.
Read a math book to learn why.

>> No.9741131

What do you have to multiply with 0 in order to get 0?

It's defined as fuck, and it's literally any number in existence.

>> No.9741138

>>9741129
What? Yes it does matter. 0/0 is a hole, a real number over 0 gives you a vertical asymptote

>> No.9741145

>>9741077
Division by zero implies multiplication by zero. The mapping defined by the operation multiplication by zero is not injective. Therefore, there is no inverse operation. Thus division by zero is undefined. QED

>> No.9741151

>>9741138
This. Undefined is not quite the same as indeterminate

>> No.9741180

Are people who insist it's undefined worthy of life?

>> No.9741184

>>9741138
please read:
>>9741145

>> No.9741195

>>9741184
You're the one who needs to reread.

>> No.9741199

It's indeterminate. So none of the above. OP was a fag today as well.

>> No.9741202

>>9741077
0/0 = %

0 divided by zero is percent

>> No.9741206
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9741206

>>9741195
My argument doesn't require the concept of asymptote, only basic set theory.

>> No.9741214

>>9741202
dang this guy's smarter than the rest of us

>> No.9741230

>>9741145
It's injective over a powerset. QED

>> No.9741240

>>9741230
>it's injective over a powerset
Take the sets with only one element. All of these are mapped to the set {0}. Therefore, the mapping is not injective over a powerset. QED.

>> No.9741259

>>9741240
Turn the arrows.

>> No.9741264

>>9741259
One set corresponds to an infinite number of sets under the mapping. Therefore not injective. QED

>> No.9741281

everyone asks "what is 1/0"? ok, cool question, yeah,, but already asked..a lot. how about: 2/0?? 3/0? instead of repeat same question over an do ver. uninspire

>> No.9741285

>>9741077
undefined
precalculus to know why

>> No.9741294

>>9741285
Calc II to know why it's indeterminate.

>> No.9741307

>people confusing expressions like [math] \lim_{x \rightarrow 0} \frac{x}{x} [/math] and the expression [math] \frac{0}{0} [/math]
I'm pretty sure it's only indeterminate if it's a limit

>> No.9741348

https://en.m.wikipedia.org/wiki/Indeterminate_form

>> No.9741542

>>9741077
>is zero/zero undefined, zero, one or infinite?
In which wheel?

>> No.9741552

>>9741542
this guy gets it

>> No.9741554

>>9741307
yeah, 0/0 is undefined

>> No.9741563

>>9741552
>this guy gets it
I'm not a "guy".

>> No.9741602

>>9741563
We're all "guy" here, but if you insist on making it an issue, show tits.

>> No.9741617

It's undefined.

>>9741542
>In which wheel?
Anything that happens in a wheel is not division. It's a generalization thereof that sacrifices some of the critical properties that defines division.

>>9741199
>It's indeterminate. So none of the above.
No. 0/0 IS an indeterminate form, but that doesn't mean 0/0 isn't undefined. Which it is.

>> No.9741817

>>9741138
>a real number over 0 gives you a vertical asymptote
False. A vertical asymptote of a function [math]f[/math] is a point [math]k \in Dom f[/math] such that [math]\lim_{x\to k^\pm} f(x) = \pm \infty[/math]. Division by zero does not exist in [math]\mathbb{R}[/math] due to field axioms.