[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math

View post   
File: 8 KB, 478x478, faulty circuit.jpg [View same] [iqdb] [saucenao] [google]
9608345 No.9608345 [Reply] [Original]

Why doesn't this circuit work? What am I doing wrong here?

>> No.9608352
File: 16 KB, 672x205, wr.png [View same] [iqdb] [saucenao] [google]
9608352

>>9608345

>> No.9608356

>>9608352
but that's not a short circuit

>> No.9608357

>>9608345
If you draw a circuit like that, then you may want to be studying a little bit more.

>> No.9608362

>>9608345
define work.
also, try using kirchhoff's laws to do analysis on the loops and junctions

>> No.9608369

>>9608356
I think it is, anon

>> No.9608377

>>9608369
how?

>> No.9608380

>>9608377
You're short-circuiting that one resistor.

>> No.9608382

>>9608380
how is that a problem for the entire circuit?

>> No.9608391

>>9608345

>Why doesn't this circuit work?

You're using a capacitor in a DC circuit.

>What am I doing wrong here?

Literally everything.

>> No.9608396

>>9608391
>>9608391
I don't understand why it wouldn't still work, I'm at a loss here

>> No.9608404

>>9608396

That's precisely why it doesn't work. You don't understand some basics. Start over and follow the foundation logic.

>> No.9608416

>>9608345
you'se using MS paint

>> No.9608421

>>9608345
I can't see anything wrong with it.

>>9608380
That isn't how it works

>> No.9608422

>>9608391
And what? What if it's a ceramic disk capacitor? And why can't you use a cap in a DC Circuit, if you check the - and + correctly?

>> No.9608427

>>9608345
What's the load? Won't this just heat up and explode?

>> No.9608432

>>9608422

It blocks DC voltage.

>> No.9608438

>>9608432
and what? the circuit still works, the part with the capacitor is just not powered since the cap is filled

>> No.9608442

>>9608345
This has gone from noob to bait territory.

>> No.9608443

>>9608438
Reported, saged, hide, ip hacked, and I am coming for your family.

>> No.9608484

>>9608345
there will be a power loss

>> No.9608577

What should it even do? Define work as
>>9608362
said.

>> No.9608588

>>9608345
>Why doesn't this circuit work?

What do you mean, "doesn't work" - what did you expect to see that you aren't seeing?

>> No.9608598
File: 4 KB, 550x198, 111.png [View same] [iqdb] [saucenao] [google]
9608598

>>9608438

No, the cap will drain the battery in seconds. This is how the circuit should look like.

>> No.9609418

is this loss?

>> No.9609477

>>9609418
Fuck

>> No.9609483

>>9608421
Brainlet here, why isn't the fact that there's a resistor in parallel with a wire not a problem? Wouldn't no current flow through the resistor?

>> No.9609867

>>9609483
Not strictly a problem, just a resistor that would be ignored. But that still doesn't really answer OP's shitty vague question.

>> No.9609895
File: 46 KB, 512x384, 1511157026333.jpg [View same] [iqdb] [saucenao] [google]
9609895

>>9608432
>It blocks DC voltage.

>> No.9609900
File: 374 KB, 2048x1365, 1506116542390 (1).jpg [View same] [iqdb] [saucenao] [google]
9609900

>>9608598
>the cap will drain the battery in seconds

>> No.9610068

>>9608345
Define "work"
Right now you have current through the two loads in the bottom right

>> No.9610075

wait a second op...

>> No.9610189

>>9610068
force times distance

>> No.9610191

>>9610189
distance raptor/time raptor = velociraptor

>> No.9610271

>>9610075
you're right

>> No.9610427

>>9610271
>>9610075
I don't get it

>> No.9610670

>>9610427
I guess the joke is lost on you.

>> No.9611087

>>9609895
The impedance of a capacitor is [math]\frac{1}{i\omega c}[/math], for DC [math]\omega[/math] is 0 so the impedance is infinite and thus no DC can pass

>> No.9611102
File: 8 KB, 597x534, what.png [View same] [iqdb] [saucenao] [google]
9611102

>>9608345
Are you trolling or something?

It's just an RC circuit. It's not really going to DO anything without some kind of active element like a transistor or op-amp or something. Also, you have a resistor with both ends connected to the same node so it won't do anything because there is no voltage across it.

>> No.9611104
File: 14 KB, 646x720, 1429904286107.png [View same] [iqdb] [saucenao] [google]
9611104

>>9611087
>using i instead of j for a circuit

>> No.9611125

>>9608345
It seems that you're at a loss of power

>> No.9611135

This is a great IQ test.
I'm gonna use it next time I interview someone.

>> No.9611272

>>9609418
this
all you guys didn't get it holy shit

>> No.9611312

>>9611135
So what field is this? Who studies this stuff? Electricians?

T.brainlet

>> No.9611315

>>9608345
>>>/v/

>> No.9611319

>>9608396
Capacitors are short circuit for DC signals.

>> No.9611332

>>9611319
That's not entirely true - if it's discharged yes it's a short circuit but if it's fully charged it's an open circuit

>> No.9611337

>>9608421
>That isn't how it works
It's common to say that when a component is bypassed with a wire, the component is shorted.

>> No.9611440

>>9611312
Electrical engineers
...with a mimetic behavior bend.

>> No.9611452

>>9608345
Specify what you mean by "doesn't work".

Regardless of your answer, that circuit in steady-state is essentially a single load, a purely linear resistor. The upper resistor is shorted and the capacitor does nothing, so you have two resistors in series and that's it.

>> No.9611469

>>9611272
>all you guys didn't get it holy shit

"I showed a meme image that looked like something board relevant on a board that isn't drowning in that meme, and people thought it was relevant instead of a meme" T. Anon, 2018, University Press Department of Auto-Ethnographies.

>> No.9611658

Why are there two positives on the bottom

>> No.9611660

>>9611658
It's a capacitor.

>> No.9611683

>>9609418
Case closed.

>> No.9611744

>>9611104
j is for engineering plebs

>> No.9611794
File: 47 KB, 987x478, steady state behavior.jpg [View same] [iqdb] [saucenao] [google]
9611794

>>9608345
effective circuit, we see that the circuit actually works

>> No.9611806

>>9608345
What's it supposed to do? I see a directional capacitor, a capacitor and three objects of unknown properties, possibly resistors.

>> No.9612346

>>9608356
you need to learn how to draw and read circuits, that IS a short circuit, it is a path of virtually no resistance between two points
study harder before posting your homework here

>> No.9612359

>>9611794
putting a capacitor in parallel with resistors does not charge the capacitor even a little?

I find that hard to believe

>> No.9612360

>>9608345
I check for secret doors

>> No.9612361

>>9611794
op said nothing about steady state.

>> No.9612620
File: 112 KB, 1018x1018, 1521573820126.jpg [View same] [iqdb] [saucenao] [google]
9612620

>>9608345
And how is that circuit even supposed to work? What should it do?

>> No.9612701

>>9612346
>>9612346
I thought short circuits(non trivial) were paths from one end of the power source to the other without resistance

>> No.9612788

>>9611744
No the fuck it is not, it's for anyone who knows how to properly analyze circuits. Granted those are usually engineers.

>> No.9612790

>>9608345
Is this Pentium processor?

>> No.9612851

>>9612359
it does
his image only analyses the circuit for the steady state when the capacitor is already charged

>> No.9612860

>>9612701

Bypassing any kind of element in the circuit via 0 resistance wire (or for example copper wire in practice) is considered to be short circuiting.

>> No.9614681
File: 24 KB, 478x478, faulty circuit.png [View same] [iqdb] [saucenao] [google]
9614681

>>9608345
R1 and R2 make a voltage divider. the capacitor is irrelevant because it's dc, and the other resistor is parallel with a short circuit.

>> No.9614703

>>9608345
>>9608598
what the fuck? in which shithole country do you draw the voltage like a capacitance?

>> No.9614956

>>9614703
not OP but
Symbol most likely specifies a battery rather than simply any voltage source. I was told to use circles with + and - for sources that can be assumed to be infinite for the purposes of the circuit, like a wall outlet and the battery symbol ones for ones that are not, like batteries.

>> No.9615625
File: 7 KB, 543x419, if_amp.gif [View same] [iqdb] [saucenao] [google]
9615625

Hey since this is the Electronics for Retards thread can I replace this IF transformer with a differential amplifier?

IF cans are hard to find and expensive compared to a few decades ago and I hate winding my own transformers. I still want good isolation between the LO and IF. Diff amp is high impedance and it allows me to impedance match easily. Throw a buffer on the output and throw a 50 ohm resistor on the output. Easy 50 ohm output impedance.