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/sci/ - Science & Math


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9472402 No.9472402 [Reply] [Original]

This should take you 10 seconds max to figure out.

>> No.9472404
File: 14 KB, 478x523, 1507361272497.png [View same] [iqdb] [saucenao] [google]
9472404

100-25pi.

>> No.9472408

>>9472404
Incorrect. You forgot to factor your answer.

25(4-π)

>> No.9472420

>>9472402
(10*20 - 2*(pi*5*5))/2 = 100 - 25*pi = 25*(4-pi)

>> No.9472501
File: 110 KB, 657x539, 1507078056361.png [View same] [iqdb] [saucenao] [google]
9472501

>>9472402
10 * 20 * 0.1

>> No.9472509

>>9472408
What difference does that make? Serious question. I'm a ((cs student))

>> No.9472511

>>9472402
21ish

>> No.9472512
File: 351 KB, 1200x900, 1517235460054.jpg [View same] [iqdb] [saucenao] [google]
9472512

>>9472509
It makes no difference my dude.

>> No.9472517

>>9472404
>>9472420
you forgot to count the line thickness

>> No.9472535

>>9472402
~21,46

>> No.9473479

21.46

>> No.9473496

>>9472402
>actual homework
>10 replies

>> No.9473499

>>9472509
It doesn't make a difference at all, it's just something teachers do to force their students to practice factoring for when it does become relevant.

>> No.9473578
File: 9 KB, 720x540, Circles puzzle.png [View same] [iqdb] [saucenao] [google]
9473578

Find length AB

>> No.9473604

>>9472402
((10*20) - ((pi*5^2)*2))/2 = 21.46

The fact that you thought this was difficult enough to warrant a thread on /sci/ means you are too stupid to be here. Please leave.

>> No.9473608

>>9473578
(1/3)OE

>> No.9473610

>>9473578
Not enough information. We cant be sure the circles are all of equal size because they aren’t labeled as such.

>> No.9473623

>>9473610
Also AB isn't the diameter

>> No.9473834

>>9473623
Also, those aren't circles. Also that's not a rectangle. Also that's not a diagonal. Also we're not in Euclidean space.

>> No.9473836

>>9472402
"hard"

>> No.9473899
File: 6 KB, 207x243, 550.png [View same] [iqdb] [saucenao] [google]
9473899

>>9473578
0.3258OE.

>> No.9473927

[math]\frac{ A_{rec}-2A_{circ}}{2}\,\,\,A_{rec}=200\,\,\,A_{circ}=25\pi [/math]

>> No.9473961

>>9473834
>it's looks it so it must be it
>durrrr

>> No.9473976

>>9473961
>durr why check the second thing?

>> No.9474123

>>9472402
25

>> No.9474161

>>9472402
10*20*0.5 - pi*25 = 100 - pi*25

>> No.9474169

>>9472517
Graphs of continuous functions have measure zero, baka

>> No.9474172

>>9472402
Prove that the combined circle area under the diagonal equals the combined circle area above the diagonal

>> No.9474176

>>9473496
It's not homework, it's a test question given to chinese students. We've seen it before which is why the answers come so fast.

https://www.youtube.com/watch?v=xnE_sO7PbBs

>> No.9474184

>>9474172
that's just like proving the bottom triangle has he same area as the top triangle
>trivial

>> No.9474190

>>9474176
I've never seen it and I got the answer immediately, it's very obvious.

>> No.9474278

>>9474184
>if it's so trivial blah blah...

>> No.9474281

>>9474176
g-g-guys... WHAT HAPPENED to the bottom left red spot!?!?

>> No.9474318

>>9472402
tanh(20)

>> No.9474472

>>9474176
>OP is a chinese student.

>> No.9474883

>>9474278
bh/2
b t f o

>> No.9474899

>>9474281
GodDAMNIT, anon!

>> No.9474914

Start with full area: 10 * 2(10) = 200

Subtract area of circles: 200 - (2 * (5^2 * pi)) ~= 42.92

Divide by two -> 21.46

>> No.9474915

10^2-pi*5^2 = 100(1-1/4pi)

>> No.9475245

>>9472509
Mathematical beauty