Formula

[Anonymous No.9298027]

4 = 12
5 = 14
6 = 18
7 = 24
8 = 30
9 = 38
10 = 50

Can someone give me the math formula?

[Anonymous No.9298053]

>>9298027

[math]f(n-2) = 11 + \frac{(n-2)^2 - (n-2)}{2} [/math]

[Anonymous No.9298057]

>>9298053

Nevermind, i dun goof'd, I read your numbers wrong

[Anonymous No.9298065]

>4 = 12
are you sure ? im pretty sure those numbers are not equal .

[Anonymous No.9298144]

>>9298027
polyfit(...);

-0.0018 0.0733 -1.2153 10.2363 -44.7738 85.9722 0 -145.2727
Is such a polynomial.

[Anonymous No.9298377]

>>9298027
I can usually see through those fairly quickly, but this is giving me a migraine. please tell me there is no pattern and you're just trolling us with random digits or that you typed the original problem down wrong

[Anonymous No.9298586]

>>9298027
I'm not a math guy, but it looks like it increases In patterns of 2 2 2 4.

[Anonymous No.9298608]

>>9298027
AWWWWWWWWWW I AM SUCH A FUCKING BRAINLEt I TRIED EVERYTHING DIVIDING POWERS ADDING SKIPPING theM
Em I mean I can't seem to find the pattern here, the most I could see is that for 4 and 6 there seemed to be a pattern where sum of the number and sum of the result of number below would produce the result of a number 2 rows below the original, so like 4+14=18, 6+24=30, but it doesn't work for 8 for some reason. The 5 and 7 on the other hand seemed to have the same thing going on, but had to add one for it to work like 5+18+1=24. 7+30+1=38 but I have no idea whenever or not would it work for 11. The 10 seems kinda pattern breaking, because pattern number+number below+result inbetween seems to be working for everything but fucking 10. 4+14+6=24. 5+18+7=30, 6+24+8=39 and then it goes down the drain. I think I've been baited but I am fucking STUPID so i get baited really really easily by these kinds of things. Why are u doing this to me OP.

[Anonymous No.9298678]

>>9298027
Or maybe every fourth number starting at zero doesn't work? Can you at least give 0, 1, 2 and 3 OP? Because 3+12+5=20=/=18, and 7+9+30=46=/=50, I think it every fourth number needs to have multiples of 2 added for the formula to work, so actually:
11=8+38+10=56
12=9+50+11=70
13=10+56+12=78
14=11+70+13+6 or 11+70+13+8
but yeah i dont think that really works either
because 3+12+5=20=/=18 which is actually 2 short, unless it's switching between adding and subtracting, but if that was the case then 2+x+4=14 so 3=8 so 1+y+3=12 so y=8 so 2=8 and then 0+x+2=8 so 1=6 and at this point i honestly dont know if any of this makes ANY sense or if u just typed random numbers to fuck with me well ill tell u what if u did u did a great job because i just wasted like an hour thinking about this shit instead of sleeping u know what OP fuck u. i fucking hate u and i hate myself and i hate everything. if i were smarter i would show u and ur dumb ass sequence where the exit is. u bully. but yeah heres my final answer
0=x
1=6
2=8
3=8
4=12
5=14
6=18
7=24
8=30
9=38
10=50
11=56
12=70
Okay i think i actually solved it now that i look at it
so heres the thing, every fourth number is a bad number, that needs to be substracted or added with number of even numbers that are above it, so for 3 it was -2 (0 and 2) for 7 it was +4 (0,2,4,6) for 11 it would be -6 (0,2,4,6,8,10) etc. so actual sequence is:
0=x
1=6
2=8
3=8
4=12
5=14
6=18
7=24
8=30
9=38
10=50
11=56
12=70
13=78
14=88
15=104 etc etc
unfortunately being as stupid as i am i cant really write cool formulas cool kids can write, so maybe someone else would do that.

[Anonymous No.9298737]

>>9298027

[math]f(n) = \sum_{l=4}^n \prod_{d|l} \phi(d) + 10 [/math]

[Anonymous No.9298767]

>F(x)=ax^8+bx^7+cx^6+dx^5+ex^4+fx^3+gx^2+hx+i
>solve system of equations
Obvi

[Anonymous No.9298775]

>>9298737

Wait this was wrong. L(n) = nth term of the Look and Say sequence. |L(n)| = length of the nth term of the sequence.

[math]f(n) = (\sum_{j=3}^n |L(j-2)|) + 9 [\math]

For completeness, here's the terms of the Look and Say sequence:

1, 11, 12, 1121, 122111, 112213, 12221131, 1123123111, 12213111213113, 11221131132111311231, 12221231123121133112213111, 1123112131122131112112321222113113

I.e. their lengths are 1,2,2,4,6,6,8,12,...

I.e. the partial sums plus 9 = 10,12,14,18,24,30,38,50

[Anonymous No.9298778]

>>9298775
[math]f(n) = (\sum_{j=3}^n |L(j-2)|) + 9 [/math]

[Anonymous No.9298785]

here anon

[Anonymous No.9300296]

bump

I'm retarded pls help me figure out this equation...

Presume that I have to take an exam with 4 questions on which 9 topics are chosen at random. I have studied well for 8 of the 9 topics. What is the likelihood that I will encounter the one question that I have not studied?

[Anonymous No.9300299]

>>9298027
Z1

[Anonymous No.9300404]

>>9300296
I don't really understand what you're trying to say.
>>>/wsr/

[Anonymous No.9300592]

>>9300296
1 - 8/9 * 7/8 * 6/7 * 5/6 = 1 - 5/9 = 4/9