/sci/ - Science & Math

[Anonymous No.9219628]

Well?

[/psy/mon|0-X's|/sci/mon No.9219630]

>>9219628
3

[Anonymous No.9219632]

isnt it 11,7,5,-3?

[Anonymous No.9219633]

>>9219632
or just generally 4 moves

[Anonymous No.9219634]

2

[/psy/mon|0-X's|/sci/mon No.9219636]

>>9219632
[math]3 == \begin{turn}{30}4\end{turn}[/math]

[Anonymous No.9219666]

Considering you can't pass the hole, 4 moves of 5 because of 20's factorization?

[Anonymous No.9219667]

>>9219666
it literally says you can pass the hole

[Anonymous No.9219671]

>>9219667

I have the bad habit of not reading problems till the end because of my third world's retarded entrance exams

then it's >>9219634

[Anonymous No.9219673]

>>9219671

meant >>9219632

[Anonymous No.9219676]

>>9219634
If he hits it 11 feet into the air at a 50° angle he can let gravity do the rest of the work so the answer is 1.

[Anonymous No.9219679]

>>9219628
Answer is 4, as all the movable distances are odd and you need an even number of moves to get to in the hole. You can't do it with 2 therefore 4 is the smallest amount of hits

[Anonymous No.9219681]

>>9219679
seems reasonable

[Anonymous No.9219684]

>>9219676

huuuuuummmmmm you can't take the ball off the ground on a put mkay? come up with a form of slope that you have the same effect

[Anonymous No.9219688]

>>9219684

would*

[Anonymous No.9219699]

>>9219684
>huuuuuummmmmm you can't take the ball off the ground on a put mkay?
That's what you think