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/sci/ - Science & Math


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9216789 No.9216789 [Reply] [Original]

Dumb anon here but can someone tell me how I would solve this and the answer? I'm bad at math :"(

>> No.9216790

Basic trigonometry.

>> No.9216799

figure it out fucking nigg nogg. If you can't solve this you won't go anywhere in life.

>> No.9216801

>>9216799
He didn't ask for his answer: E

>> No.9216819

>>9216789
For you it would be E.

>> No.9216825

>>9216789
>asking this question.
F

>> No.9216828

Jesus christ anon.

I'll give you one hint: what is the circumference of a circle with radius r expressed in terms of the angle subtended by that circumference?

>> No.9216841

>>9216828
0

>> No.9216851

>>9216789
B anon. When most of these people flex about their own intellegence but don't even answer the question. Geez I wonder why

>> No.9216857

>>9216851
S=r(degree) so it would he 10.8=r(1.8). Dividing 10.8 by 1.8 would equal to r which is why it's 6

>> No.9216859
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9216859

>>9216828
2pir=1.8/2pi?

>> No.9216862 [DELETED] 

>>9216859
Hm...

Hello world.

>> No.9216881

>>9216789
nigga θ = arclength/radius

>> No.9217102

>>9216859
S=(thetha)/2n
Multiply that by 2nr to find the arc length(s). Or simply s=(thetha)r

>> No.9217362

>>9216881
>>9217102
hyperbolic paraboloid

Odd way to say hello. Can you do any tricks? Or help a negger out?

>> No.9217400

>>9216789
Anon, what is 10.8/1.8?

>> No.9217402

>>9216789
its 10.8/1.8
because 1.8 is measured in radians
radius times angle in radians = arc length

>> No.9217406

>>9216789
Since E is even an option, I assume there's not a penalty for being unable to answer, in which case coming here for help is pretty pathetic.

>> No.9217414 [DELETED] 

>>9217406
F

>> No.9218705

>>9217406
he asked for an explantion not just the answer cunt but that looks like khan academy and that shit gives you a lesson so he kinda retarded

>> No.9219175

You're computing radian measure.
I don't know how to write equations on this board like everyone else so bear with me here.

Radians equal the arc length (s) divided by the radius.