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/sci/ - Science & Math


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8486499 No.8486499 [Reply] [Original]

Without using google, or cracking open a book or anything; using only knowledge and information currently in your brain. answer this question:

If you were on the Moon looking at Earth right now, would Earth's north pole, or south pole be closer to "up" from your perspective?

Please give your best guess, and your reasoning why.

(If your reasoning depends on a specific place, take the site of the first moon landing)

>> No.8486505

That entirely depends on where the first moon landing was.

>> No.8486506

>>8486499
North. Because I live in the north. Also, because it's so cold up here, my penis shrinks to a stack of dimes when I go outside. That last part was just a random fact.

>> No.8486507

>>8486499

I could see either side up depending on where I am on the moon.

>> No.8486521

>>8486499
Don't know. Even taking the position of the first moon landing (which I think was below the equator a little bit?) isn't enough because I don't know the position of the Moon in its tilted orbit around a tilted Earth.

>> No.8488320

>>8486499
South pole.

We are close to December meaning Earth's south pole is sunlit and north pole is dark.

Moon is visible at night meaning it was full, so it is soon new, meaning it is on the sun side from Earth.

This from the Moon you seethe same face as from the Sun: and since the north pole is dark you see the south pole.

>> No.8488322

It depends on which part of the moon I'm on. I don't know the site of the first moon landing on the moon without Google so I have to leave my answer at that.

>> No.8488345
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8488345

>>8486507
/Thread

>> No.8488346

>>8486499
North. The moon is at about 30 something degree inclination to the earth

Even from the south of the moon, the north would be closer

>> No.8488696

>>8486506
He has small penisesss ayyy lmao

It's ok scitard, I suffer from the same disorder.

>> No.8489507

Neither I'm blind.

>> No.8489527

>>8488346
Yeah, but that means it'll be at a -30 inclination at the opposite point of its orbit.