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/sci/ - Science & Math

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Is it true that 1 - .99 repeating is zero?

 >> Anonymous Thu Apr 7 09:41:49 2016 No.7985560 Yep.
 >> Anonymous Thu Apr 7 09:49:57 2016 No.7985572 >>7985559nope, since it still holds a value it cannot be zero. Zero has no value.
 >> Anonymous Thu Apr 7 09:50:25 2016 No.7985573 >>7985572wrong
 >> Anonymous Thu Apr 7 09:54:25 2016 No.7985582 >>7985573Please explain how it is wrong, isn't it just like 0.999.. will never be one?
 >> Anonymous Thu Apr 7 10:07:38 2016 No.7985599 >>7985582But 0.999...= 1
 >> Anonymous Thu Apr 7 10:08:28 2016 No.7985601 >>7985582Ever taken a limit?
 >> Anonymous Thu Apr 7 10:09:31 2016 No.7985603 >>79855999 repeating is not the same as 99 repeating. 99 is bigger than 9.>>7985601The limit is only a hypothetical point at infinity and never reached.
 >> Anonymous Thu Apr 7 10:45:02 2016 No.7985669 >>7985603are you still in high school, kid?
 >> Anonymous Thu Apr 7 10:55:08 2016 No.7985687 >>7985603>The limit is only a hypothetical point at infinity and never reached.That's a real shame considering the real numbers are essentially defined as limits of Cauchy sequences.
 >> Anonymous Thu Apr 7 10:56:46 2016 No.7985690 >>7985599Die in a fire uneducated ignorant cuck
 >> Anonymous Thu Apr 7 13:07:58 2016 No.7985909 >>7985559If 1 - 0.999... were not 0 then it would have to be some real number greater than 0
 >> Anonymous Thu Apr 7 13:13:22 2016 No.7985918 >>7985669>questioning the establishment equates to being immature.
 >> Anonymous Thu Apr 7 13:58:42 2016 No.7986002 >>7985909It's 0.000...1 obviously.
 >> Anonymous Thu Apr 7 15:54:23 2016 No.7986199 >>7985603>>79856901/3 = 0.333...3/3 = 0.999... = 1>get gut faggots
 >> Anonymous Thu Apr 7 16:09:28 2016 No.7986223 >>7986002If it isn't 0 than what is 1/0.000...1 ?What's 0.000...1 times 10 ?What's 0.000...1 divided by 10 ?What's (0.000...1)^2?
 >> Anonymous Thu Apr 7 16:44:00 2016 No.7986289 >>7986223>$\infty - 0.000 ... 1$>0.000...10>0.000...01>0.000...000...1Try harder.
 >> Anonymous Thu Apr 7 17:21:36 2016 No.7986354 1/3 = 0.3..3/3 = 0.9..3/3 = 10.9.. = 11-1 = 0
 >> Anonymous Thu Apr 7 18:18:08 2016 No.7986485 >>7985559x=0.99999...10x=9.99999...10x-x=9.9999..-0.9999..=9=9x9x=9x=10.999../3=0.3333..0.3333..=1/31/3*3=1=0.9999..0.9999..=1
 >> Anonymous Thu Apr 7 19:31:52 2016 No.7986607 x=0.000...110x=00.000...110x-x=0.000...1-0.000...19x=0x=0
 >> Anonymous Thu Apr 7 19:40:13 2016 No.7986619 >>7986289I can't - you've convinced me that 1 != 0.999...
 >> Anonymous Thu Apr 7 22:26:54 2016 No.7986884 >>7986354(1/3)*3 = 1.333... * 3 ~= 1problem with rounding, computers cant store more than x amount of decimals for calculations.
 >> Anonymous Thu Apr 7 22:53:38 2016 No.7986935 it's a 0.0, followed by an infinite string of zeroes, except that on the end of that infinite string of zeroes, there's a fucking zeroit's fucking nothingi fucking hate this fucking memefuck
 >> Anonymous Thu Apr 7 22:57:45 2016 No.7986939 File: 35 KB, 500x330, 1424557007846.jpg [View same] [iqdb] [saucenao] [google] [report] yesss these threads never get old
 >> Anonymous Thu Apr 7 23:02:33 2016 No.7986953 File: 106 KB, 953x613, 0.999 = 1.jpg [View same] [iqdb] [saucenao] [google] [report] $x = 0.99\bar{9}$$10x = 9.99\bar{9}$$10x - x = 9.99\bar{9} - 0.99\bar{9}$$9x = 9$$x=1$but earlier we said that $x = 0.99\bar{9}$therefore,$0.99\bar{9}=1$end of proof
 >> Anonymous Thu Apr 7 23:04:43 2016 No.7986959 >>7986884>.333... * 3 ~= 1false.0.333... = 1/3 therefore 0.333...*3 =1
 >> Anonymous Thu Apr 7 23:04:54 2016 No.7986960 >>7986884No 0.333.... is actually perfectly equal to 1/3
 >> Anonymous Thu Apr 7 23:20:06 2016 No.7986983 >>7986953Point 1 in yellow is right. Point two shouldn't even come into discussion because 1 - 0.333... isn't the same as "0.666...7". Pic needs the trick for getting fractions out of repeating decimals.
 >> Anonymous Thu Apr 7 23:24:12 2016 No.7986988 Infinity doesn't exist, it is an abstract concept. So the 9's can not repeat for ever, there must be a limit.
 >> Anonymous Thu Apr 7 23:24:55 2016 No.7986991 >>7986988Math =/= reality
 >> Anonymous Thu Apr 7 23:35:53 2016 No.7987009 File: 160 KB, 480x800, wp_ss_20160324_0002.png [View same] [iqdb] [saucenao] [google] [report] >>7986988Jumping off what this guy said, I always thought infinite numbers didn't exist in reality? .999... does not occur in the universe
 >> Anonymous Thu Apr 7 23:39:56 2016 No.7987010 >>7987009Well it does, because its the same thing as 1
 >> Anonymous Thu Apr 7 23:47:02 2016 No.7987020 >>7986953Slight error there.9.(999...) - 0.(999...9) = 99.(999...) - 0.(999...) =/= 90.(999...) = 1 for other reason.Its is because (999..) = | 1 | of a higher cycle, as "9" is the highest possible digit of the base-10
 >> Anonymous Fri Apr 8 00:27:35 2016 No.7987077 >>7986289if 0.000...1 * 10 = 0.000...10then 0.000...1 * 10 = 0.000...1divide by 0.000...1 on both sides and we get 10 = 1which doesnt make sensealso 0.000...1^2 = 0.000...000...1so 0.000...1^2 = 0.000...1and for x^2=x. the solutions are x = 0 and x = 1so 0.000...1 is either equal to 0 or 1
 >> Anonymous Fri Apr 8 00:36:06 2016 No.7987091 >>7987009But .999... is rational so its alright
 >> Anonymous Fri Apr 8 00:39:39 2016 No.7987096 >>7986953Literally all of these and every single proof for this relies on approximation fallacies.
 >> Anonymous Fri Apr 8 00:40:49 2016 No.7987098 All this argument does is highlight the fact that our system of math doesn't quite represent reality, as well as the failures of approximation in the realm of theory.
 >> Anonymous Fri Apr 8 00:46:19 2016 No.7987105 >>7987009It does though. It's 1.
 >> Anonymous Fri Apr 8 01:04:56 2016 No.7987126 >>7985582It's wrong because 0 is a value. If I have a set which contains only 0 and another set which is empty (the empty set), these sets are not equal. Thus 0 is a value. You are wrong.
 >> Anonymous Fri Apr 8 01:07:12 2016 No.7987129 >>7986988You don't fucking understand what you're saying.1, 2, 3, none of these numbers exist. Literally every number is an abstract concept because that's all numbers are.Math is not physics. Stop conflating the two.
 >> Anonymous Fri Apr 8 13:32:06 2016 No.7988125 How can the limit as x approaches 1 of 1/(1-x) be infinityIFThe limit as x approaches 0 of 1/(1-x) = 1?
 >> Anonymous Fri Apr 8 13:36:09 2016 No.7988132 >>7988125To clarify, I don't get this because in the first one, you're basically saying that x will never become 1, otherwise it will be undefined. So, how can x become 0 in the bottom one to give the limit = 1? If you follow the same rule as the first one, that it never reaches 0, then the answer must be greater than 1?
 >> Anonymous Fri Apr 8 14:03:05 2016 No.7988188 >>7987096No. Don't confuse what you see written with what is expressed.0.999... and 1 ARE the same because these symbols MEAN the same. Just like 'horse' and 'paard' mean the same.
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