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/sci/ - Science & Math

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7710345

Function Anonymous Wed Dec 9 12:22:17 2015 No.7710345 [Reply] [Original]

y=(3)/sqrt^3(x^2-27)

Anybody knows what to do?

>>	The UNIVERSE Wed Dec 9 12:27:16 2015 No.7710358 Yes, listen to yourself and the answers will come. See? >>7710221

>>	Anonymous Wed Dec 9 12:30:22 2015 No.7710369 I just needed some help... It's really bugging me.

>>	Anonymous Wed Dec 9 17:26:45 2015 No.7710937 just be yourself anon !

>>	Anonymous Wed Dec 9 17:28:47 2015 No.7710942 >>7710345 >Anybody knows what to do? Of course not, you didn't even say what you are supposed to do.

>>	Anonymous Wed Dec 9 17:32:54 2015 No.7710949 >>7710345 y=(3)/(sqrt(x) -3) x= 1 y = 3/(sqrt(1)-3) y = 3/1-3 y = 3/-2

>>	Anonymous Wed Dec 9 17:34:34 2015 No.7710950 >>7710949 y = (3)/(sqrt^3(x^2 - 27) y = (3)/(sqrt(x) - 3) x = 1 y = 3/(sqrt(1)-3) y = 3/1-3 y = 3/-2

>>	Anonymous Wed Dec 9 17:43:13 2015 No.7710968 >>7710345 >>7710949 >>7710950 Sorry Function: X has to be greater than sqrt(27) which is approximately 5.1961. Conversely, it has to be less than its negative which is ~ -5.1961.