/sci/ - Science & Math

[Anonymous No.7409819]

Prove me wrong

[Anonymous No.7409821]

when you're taking the log of a complex value you have to take a branch cut otherwise it's multivalued. you're not doing this and that's why it's wrong.

[Anonymous No.7409824]

>>7409819
Prove me wrong
>1+1=2
>1=2
You're right a 1 can equal a 2
Good job buddy. Pats head*

[Anonymous No.7409829]

>>7409821
this

[Anonymous No.7409834]

>keeps going on the contradiction until he gets 1 = 2 instead of the obvious contradiction at 2ipi = 4ipi
Look at him! Look at him and laugh!

[Anonymous No.7409839]

an·ti·log·a·rithm cannot be zero
Done.

[Anonymous No.7409840]

>>7409824
>thinks it's the same thing

[Anonymous No.7409850]

Guys this is a bait thread.

[Anonymous No.7409857]

an·ti·log·a·rithm cannot be one
Y = ln(a) where a is bigger than zero and doesnt equal 1

[Anonymous No.7409868]

>>7409821
Says who, faggot?

Ln(x) is defined as the function exp(x) reflected in the line x=y , so it should always be the case that ln(exp(x)) = x no matter what x may be
Your argument has to invalidate this reasoning

[Anonymous No.7409915]

>>7409868
That's not the definition of Log.

The definition is Log(z) = ln(|z|) + iArg(z)

[Anonymous No.7409936]

>>7409819
I'll beat you at your own game
replace the right side with e^0, and using the same logic, 2*pi*i = 0
therefore pi*i = 0
therefore you divided by zero
>inb4 my proof is wrong
yes I know, but it disproves OP according to OP's rules

[Anonymous No.7409990]

>>7409915
Says who you fuckin little queer?

What is wrong with defining it exactly as I have defined it, as the inverse of exp ?

[Anonymous No.7409998]

>>7409990
The fact that it's a retarded and inconsistent definition

[Anonymous No.7410005]

>>7409868
>reflected in the line
you are not in the line, you are in the complex plane

[Anonymous No.7410013]

>>7409990
It is, as the OP has demonstrated, not well defined, as there are multiple inverses and you have omitted to mention which to pick (which can be done via a branch cut)

[Anonymous No.7410027]

>>7409990
Think about what you are even writing.

Because, if you didn't remember, it's <span class="math">e^{i\theta} = \cos(\theta) + i\sin(\theta)[/spoiler]

So what you're actually saying is that <span class="math">\cos(2\pi) = 1 = \cos(4\pi)[/spoiler] implies that <span class="math">2\pi = 4\pi[/spoiler]

Which I don't need to tell is not true, because the function is periodic.
The same happens with the exponential function in the complex plane, as it a combination of sine and cosine, it is also a periodic.

That's right, the exponential function IS A PERIODIC FUNCTION IN THE COMPLEX PLANE.
Thus, the same way you define arctan, arcsin, whatever else, you have to RESTRICT THE DOMAIN, ie, you have different arguments, thus different logs.

[Anonymous No.7410030]

>>7409990
haha consensus says youre a retarded faggot
learn to math you fuckin little queer

[Anonymous No.7410044]

>>7410027
Ok , good.
Isn't it more satisfactory to give a response that pins down why the other person is wrong instead of merely saying why you're right?
>>7410030
Watch your mouth you little buttfuckkid or I'll nigger your asshole.

[Anonymous No.7410056]

I dont think ln( ) works the same with complex numbas

[Anonymous No.7410059]

>>7409821
/thread

[Anonymous No.7410191]

>>7409819
e^iπ = -1
Knowing that x = e^ln x,
ln -1 = iπ

I believe we need more study on negative logarithms.

[Anonymous No.7410239]

>>7409819
2 and 4 give you the same output when plugged into the equation so 2 and 4 are equivalent inputs but they aren't equal.

[Anonymous No.7410262]

>>7409936
Where do you divide by zero and how do you disprove OP? You just show another error

[Anonymous No.7410302]

>>7409819
Actually learn how to apply ln to complex numbers before you guess and hurt yourself.

https://en.wikipedia.org/wiki/Complex_logarithm

[Anonymous No.7410724]

>>7410044
kill self with maximum haste

[Anonymous No.7410727]

>>7409868
But that's wrong you retard.

[Anonymous No.7410736]

sin(0) = 0
sin(2 pi) = 0

0 = 2 pi

[Anonymous No.7410741]

>>7410044
>hurr he pointed why i was wrong

you claimed to be right and spouted bullshit, everyone told you you had the definition wrong and you didn't bother to look it up

you're a stupid autist

[Anonymous No.7411035]

>>7409990
it is the inverse of exp. As exp is defined on the complex numbers. In order for this to hold, it is a multivalued function, since the complex exponential is not one to one.

[Anonymous No.7411039]

>>7410027
zingo

[Anonymous No.7411111]

I was actually correct nigga.
Says who? Math, u shit

[Anonymous No.7411123]

>>7409819
Wouldn't be exact.
etci=-1 is not correct at all.
The formula wouldn't allow that pattern to be put in to such a perspective due to the high rises in the in(e2ti).

[Anonymous No.7411124]

you should use the same branch cut
that s why your work is wrong

[Anonymous No.7411130]

>>7409821
This. A complex number is not a real number, it's better to think of it in terms of tensor/vector rather than a scalar.

[Anonymous No.7411167]

you could as way do something like this:

1 = 1
cos(2pi) = cos(4pi) | arccos
2pi = 4pi

this is equally retarded

[Anonymous No.7411183]

>>7409819

sin(90º) = 1
sin(270º) = 1
90 = 270
OP is a faggot

[Anonymous No.7411215]

oh wow its this thread again you must be such a cool dude op

[Anonymous No.7411277]

>>7409868
In real numbers, you're right. i isn't a real.

[Anonymous No.7411353]

>>7411183
>sin(270º) = 1
this nigga

[Anonymous No.7411721]

>>7409819
you doing it wrong, though you get somehow the correct result:
<span class="math">e^{2 \pi i} = e^{4 \pi i}[/spoiler]
<span class="math">2 \cdot e^{ \pi i} = 4 \cdot e^{\pi i}[/spoiler]
<span class="math">2 = 4[/spoiler]
<span class="math">1 = 2[/spoiler]

[Anonymous No.7411737]

>>7411721
retard

[Anonymous No.7411840]

>>7411183
>sin(270º) = 1
You're not much better.

[Anonymous No.7411929]

>>7409819
<span class="math">
e^{\pi i}=-1
e^{2\pi i}=1
e^{4\pi i}=1
1=1
ln(1)=ln(1)
0=0
0=0
0=0[/spoiler]

[Anonymous No.7411950]

>>7411929

<div class="math">e^{\pi i}=-1</div> <div class="math">e^{2\pi i}=1</div> <div class="math">e^{4\pi i}=1</div> <div class="math">1=1</div> <div class="math">ln(1)=ln(1)</div> <div class="math">0=0 \\ 0=0 \\ 0=0 </div>

[Anonymous No.7413689]

>>7410044