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So if we divide a number for example a/bthen a/b*b=aSo what if we divide 1 by 100we get 0.010.01*100 = 10.01+0.01+0.01...x100 = 1now we substract 0.010.01...+ 0.01 x99 = 0.99what if we make the number we divide by bigger?1/10^100then we get something like0.000...1Shouldn't still 0.000...1*10^100=1?so 0.000...1+0.000...1 x10^100 = 1now again we substract0.000...1 + 0.000...11 x(10^100-1) = 0.999....BUT!isn't 0.999... = 1?so then0.000...1 + 0.000...1 x (10^100-1) = 1 ?and 0.000...1 + 0.00...1 x 10^100 = 0.000...1 + 0.00...1 x (10^100-1)but wouldn't that be false?Are you saying 0.000...1 = 0?but then 1/10^100 = 0 and 1/10^100*10^100=0 and not 1I am legitimately confused.

>>7015159Basic logic dictates that 0.99 repeating is less than one.Mathematic logic can be "tricked" into resulting in the idea that 0.99 repeating is equal to one, only because "repeating" is an imaginary concept in the human mind. There is no such thing as an infinitely small number, so 0.99 repeating is just an idea, not a real number.

>0.000...1Oh look, it's you againCan't you just learn what a limit is and fuck off?

<span class="math">\lim_{x\to -\infty} 10^x = 0[/spoiler]<span class="math">\lim_{x\to \infty} 10^-x*10^x = \lim_{xto \infty} 1 = 1[/spoiler]<span class="math">\lim_{x\to\infty} -(10^x) + \sum\limits_{i=1}^x 9*10^-x = 0[/spoiler]Now get the fuck out with this pleb shit.

>>7015159Finally a use for this. Pic related.Sage all dayLearn limits OP

<span class="math">\displaystyle1 = \frac{3}{3} = 3 \cdot \frac{1}{3} = 3 \cdot 0.\overline{3} = 0.\overline{9}[/spoiler]

>>7015162I always thought basic logic dictated you know shit

>>7015159>0.000...1

>0.000...1This can only have finite amount of zeros. If it had uncountable zeros the it would be0.000... which is zero.

>>7015159This shitty surface dwelling crap again?N != QGo learn some number theory.

How do I use Barnett's identity to prove that 0.9999...=/=1