/sci/ - Science & Math

[Anonymous No.6548233]

So guys, E = mc^2
but we also know that for any right angled triangle a^2 + b^2 = c^2

Can't we just put E = m(a^2 + b^2) or a^2 + b^2 = E/m to get a relation between any triangle and energy of anything? It seems logical as triangles are ofund EVERYWHERE and einstein describes the energy of everything

[Anonymous No.6548259]

>>6548233
I love these posts

[Anonymous No.6548264]

>>6548233
>tldr
speed of light2 = hypotenuse2

[Anonymous No.6548273]

>>6548233
Oh. My. God.

Someone inform the Nobel Prize Committee!

[Anonymous No.6548577]

E=mc2 is a simple special case of <span class="math"> E^2 = (mc^2)^2 + (pc)^2 [/spoiler]

[Anonymous No.6548583]

>>6548577
This. For an object that isnt moving, or moving at low speed, momentum is equal to near 0 so thus E=mc^2

If an object is massless, then energy is equal to the momentum times the speed of light.

Th equation that this guy posted is the full equation, and corresponds to a right triangle, where E is the hypotenuse. Thus, for an object that has any mass, the energy will never quite equal the momentum times the speed of light, or behave like light.

[Anonymous No.6548597]

>>6548233
>So guys, E = mc^2
First off, you can cross out mass. And forget about any pesky exponents. Therefore, light is energy.
You should be able to figure out how to proceed from here on on your own.

[Anonymous No.6548634]

Whoa man