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/sci/ - Science & Math

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6528894 No.6528894[DELETED]  [Reply] [Original]

If 1=0.999999.., then shouldn't 0.99999... have an equal but infinitely smaller pair too? And if so, wouldn't that prove 1=0?

#mindblown #bazinga

>> No.6528896

The only number that actually exists is 1 anonymous.

>> No.6528905

>>6528894
No, because the number smaller than 0.999... would be 0.999 with an arbitrary number of 9's but less than infinity, there is no way to decide what that number would be.

>> No.6529282

bump

>> No.6529285

>>6528896
This. One times this.

>> No.6529313

Using the same method of proof that 1 = .999..., try out your new proposition and see how it does.

>> No.6529366

0.999999... is just a different notation of 1. It has no independent translation in reality.

>> No.6529377

The number infinitely smaller then .999... is .999...8, infinite amount of nines infront of the eight causes it to be .999... inifinite series do not like you.

>> No.6529573

>>6528905
You have omega 9s, then one eight, then omega more 9s

>> No.6529596

>>6529573
No because that would equal 0.99999...90000000... just like

0.5 = 0.499999999.....