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Anonymous Mon Mar 31 15:07:07 2014 No.6451428 [DELETED]

[Reply] [Original]

I thinking today, I know an irrational times a rational is always irrational. but what is an irrational times an irrational? I can think of like (root2 )^2, which is a product of irrationals equaling a rational. but this doesn't always happen. root2 times pi for example, is irrational.

Is there a general rule for this?

>>	Anonymous Mon Mar 31 15:12:07 2014 No.6451434 >>6451428 Not yet. If you can prove it and find out that e times pi is transcendental (or not!) then you'll probably be pretty famous.

>>	Anonymous Mon Mar 31 15:14:08 2014 No.6451437 >>6451428 >>6451434 just as a point to start poking around for your interest, see for instance http://en.wikipedia.org/wiki/Schanuel%27s_conjecture

Anonymous Mon Mar 31 15:16:37 2014 No.6451439

A general rule? Not really. You might want to look at the different between algebraic numbers (which is stuff like roots) and transcendental numbers (which is stuff like pi and e).

Also, I guess remember the rules for multiplying roots, it should become obvious when you're going to get a rational result.

>>	Anonymous Mon Mar 31 15:23:37 2014 No.6451454 >>6451428 >I know an irrational times a rational is always irrational Pi*0

>>	Anonymous Mon Mar 31 15:24:07 2014 No.6451456 >>6451434 interesting. pretty cool how such a simple thing it seems on the surface, yet no one has been able to prove it

>>	Anonymous Mon Mar 31 15:25:07 2014 No.6451458 >>6451454 Zero is an irrational number fucktard

>>	Anonymous Mon Mar 31 15:27:07 2014 No.6451463 >>6451458 Irrational numbers are numbers that cannot be expressed as a ratio p/q where p and q are integers and q != 0. 0 = 0/1. 0 and 1 are integers, and 1 != 0. So zero is rational, not irrational.

>>	Anonymous Mon Mar 31 15:30:37 2014 No.6451469 >>6451456 >reals >simple reals are retardedly complicated and stuffed with too much information, they're the "dark numbers" of mathematics >can't solve it in the rationals? >just invent numbers which magically solve it!

>>	Anonymous Mon Mar 31 15:36:07 2014 No.6451485 >>6451463 >Irrational numbers are numbers that cannot be expressed as a ratio p/q where p and q are integers and q != 0. Those are real numbers, you tool.<span class="math">\mathbf{R}[/spoiler]

>>	Anonymous Mon Mar 31 15:37:08 2014 No.6451489 >>6451469 Complexes are darker.

>>	Anonymous Mon Mar 31 15:39:07 2014 No.6451495 File: 44 KB, 622x626, dead can peace.jpg [View same] [iqdb] [saucenao] [google] >>6451485

>>	Anonymous Mon Mar 31 15:44:37 2014 No.6451500 >>6451485 0/10

>>	Anonymous Mon Mar 31 15:46:07 2014 No.6451505 >>6451495 p/q, where q is much larger than p

>>	Anonymous Mon Mar 31 15:46:07 2014 No.6451506 >>6451489 We need to go darker. http://www.xamuel.com/dark-calculus/

>>	Anonymous Mon Mar 31 15:53:26 2014 No.6451519 >>6451463 >0 is an integer >therefore it is irrational

>>	Anonymous Mon Mar 31 16:05:26 2014 No.6451560 i like the non constructive proof that an irrational to the power of an irrational can make a rational

>>	Anonymous Mon Mar 31 16:07:26 2014 No.6451571 >>6451560 Either A is true, either A is not true, bitch.

>>	Anonymous Mon Mar 31 16:07:26 2014 No.6451574 File: 69 KB, 268x326, kronecker.gif [View same] [iqdb] [saucenao] [google] >>6451560 Of what use is your marvelous proof, since irrationals do not exist?

>>	Anonymous Mon Mar 31 16:08:26 2014 No.6451575 >>6451571 Was that a typo? was the second either meant to be an or?

>>	Anonymous Mon Mar 31 16:09:56 2014 No.6451582 >>6451574 >use >mathematics

>>	Anonymous Mon Mar 31 16:10:57 2014 No.6451585 File: 20 KB, 180x215, 1390144985078.jpg [View same] [iqdb] [saucenao] [google] >>6451575 > tfw can't use a keybaord propely.

>>	Anonymous Mon Mar 31 16:10:57 2014 No.6451586 >>6451574 >exist exists in what sense? some people think whole numbers don't "exist".

>>	Anonymous Mon Mar 31 16:24:15 2014 No.6451618 >>6451586 Squaring the circle is impossible, therefore pi does not exist.

>>	Anonymous Mon Mar 31 16:27:46 2014 No.6451627 >>6451618 you mean sqrt(pi) does not exist

>>	Anonymous Mon Mar 31 16:52:45 2014 No.6451685 >>6451627 You meant sqrt(pi) is not algebraic.

>>	Anonymous Mon Mar 31 16:53:45 2014 No.6451686 >>6451685 not every algebraic number is ruler and compass constructable.

>>	Anonymous Mon Mar 31 17:02:15 2014 No.6451700 >>6451686 Example ?

Anonymous Mon Mar 31 17:08:15 2014 No.6451706

>>6451469
not this shit again
>can't solve it in the naturals, just invent integers!
>can't solve it in the integers, just invent rationals!
depending on the question, all number systems have pretty hard question. Good luck describing Gal(Q,\bar{Q}) for example

>>	Anonymous Mon Mar 31 17:13:45 2014 No.6451717 >>6451700 cube root 2

>>	Anonymous Mon Mar 31 18:08:31 2014 No.6451847 File: 57 KB, 600x434, 1389525806568.png [View same] [iqdb] [saucenao] [google] >>6451717

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