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[Anonymous No.6421546]

Chemistry fags I need your help regarding this reaction. So 1. reacts with 2 and 3 to 4. I understand that 2 Acetyl Chloride and 3 Methanol form Methyl acetate but what happens next?

[Anonymous No.6421576]

[Anonymous No.6421727]

[Anon No.6421751]

Anon's right about it making the anhydride. You can't do this in the presence of the MeOH initially because it will quench the AcCl as you already figured out. This must be a 2 step reaction.

[Anonymous No.6421818]

>>6421576
That doesn't make any sense.

You'd probably get the correct product if you just refluxed with MeOH, it should do the acetylation readily to give the ester and refluxing an alcohol with a carboxylic acid should also give the ester plus water. I'm struggling to see what the AcCl is doing here. The formation of HCl might catalyse the hydrolysis of the anhydride by forming the acetyl chloride and the carboxylic acid which could then react with the MeOH but it seems convoluted and ineffecient

[Anonymous No.6421837]

>>6421818
Full mech, because I'm not sure I'm right but it makes more sense than the other guys

[Anonymous No.6421840]

>>6421837
Piss

[Anonymous No.6421913]

>>6421837
>>6421818
>>6421751
>>6421840
OP here. Thanks so much guys. It finally makes sense for me.

[Anonymous No.6422208]

>>6421840
You need to protonate the carbonyl group before you attack it with the chloride.