emf

[Anonymous No.6142989]

anyone kind enough to help? awesome coloured pic in return.

1. The problem statement, all variables and given/known data
A step down transformer, 2400/240 V, 50Hz has the following resistance and leakage parameters.
Z1 = R1 + jX1 = 4 + j12 Ω
Z2 = R2 + jX2 = 0.04 + j0.12 Ω

The transformer is operating at 80% of its rated load. The power factor of the load is 0.866 leading.
Determine the induced EMF in the primary side

2. Relevant equations

E = 4.443 f N B A
Ni = Hl = R phi
phi = BA
E = N d(phi)/dt

3. The attempt at a solution
I don't know how to solve for N and phi. It's as if I'm leading nowhere.
So far, I've got

Attempt 1:
a = V1/V2 = 2400/240 = 10
i1 = 2400/(4 + j12) = 60 - j180 = 189.7 cis (-71.57)
but then if I try to use Ni=Hl I get stuck on finding H from B=uH

Attempt 2: Try solving for N with L
L = N^2/R
N = sqrt(LR)
R = 4 + j12
Substitute L = N^2/R into N = sqrt(LR) you just end up with N = N (nothing useful)

Attempt 3: Transfer Z2 from the secondary side over to the primary side

a= 2400/240 = 10
a^2 = 100
Z2' = 100 (0.04 + j0.12) = 4 + j12
Zeq = Z1 + Z2' = 2 (4 + j12) = 8 + j24
Then using Ni = R phi
i = 2400/(8+j24) = 30 - j90 A
R = 8 + j24
Then get stuck on finding phi...

Attempt 4: using V1/V2 = N1/N2
2400/240 = N1/N2
Assume 100 turns in N1, then N2 = 10 turns.
and let phi = i
then E = 4.443 (50) (100) (60-j180) = some massive number in MegaVolts

I've searched and searched in lecture notes for anything to do with the turns ratio, but can't find anything useful.

Please help.

[Anonymous No.6143026]

>>6142989

>you will never be in this photo
>sadfrog.jpg

[Anonymous No.6143037]

>>6143026
>not photoshoping yourself into famous historical pictures to convince strangers you are an immortal wizard that has been shaping the course of world events for centuries
Step up your game anon

[Anonymous No.6143114]

OP here

> tl;dr find induced EMF in primary coil in single phase transformer

[Anonymous No.6143123]

>>6143114
>no hw threads