Math Question (no not homework)

[Anonymous No.5816934]

\int_{0}^{1} \frac{cos(x)}{sin(x)^{3}-4sin(x)}
I got this floozie on my Calc III exam today, I keep on trying to solve it and there seems to be no quick way of doing it. Maybe I'm missing something. Halp guise, also first time using LaTeX so be gentle on my anus.


Also he asked for the center and radius of a circle in polar coordinates, but I gave it to him in Cartesian after converting from the polar equation he gave me to cartesian. Did I do wrong? I have no idea how to show the radius and center of a circle in polar...

[Anonymous No.5816936]

>>5816934
Oh boy I fucked up. Let me try again.
<span class="math">\int_{0}^{1} \frac{cos(x)}{sin(x)^{3}-4sin(x)}[/spoiler]

[Anonymous No.5816939]

>>5816936
Okay, one last time.
<span class="math">\int_{0}^{1} \frac{cos(x)}{sin(x)^{3}-4sin(x)}[/spoiler]

4chan really needs a preview posting system.

[Anonymous No.5816948]

Christ I feel retarded, can someone help out?

[The Tourist !!zaCQyFZeSRS No.5816962]

>>5816948
Is it supposed to be cos(x)/(sin^3(x)-4sin(x))?

[Anonymous No.5816965]

>>5816962
Yes, in an integral between 0 and 1.

[The Tourist !!zaCQyFZeSRS No.5816975]

>>5816965
I tried to factor one sin(x) out from the denominator, substitute u=sin(x) and then use partial fraction decomposition to get a nice integrand with 3 elementary terms but after that the integrand didn't converge (Wolfram agrees) so you might want to check with your professor on that one.

[Anonymous No.5816977]

>>5816939
It's not your fault, jsMath is broken right now.
>>>/q/623173

[Anonymous No.5816979]

>>5816975
Not everyone's doing babby calc.

[The Tourist !!zaCQyFZeSRS No.5816985]

>>5816979
I'm not sure what you're getting at.

[Anonymous No.5816990]

>>5816975
I thought about doing that, but then I was running out of time and I figured there must have been a quicker way.

[Anonymous No.5816992]

>>5816975
OP again, >>5816990
Well we're doing improper integrals so I could just tell him that it diverges. Also I asked him if I could see the paper next week or something, he told me no.

[Anonymous No.5816997]

>>5816990
The quick way would be noticing the integrand is O(-1/(4x)) near the origin, which means it diverges.

[Anonymous No.5817015]

>>5816997
I'm sorry, I dont follow.