/sci/ - Science & Math

[Anonymous No.5644851]

<span class="math">
\frac{x+1}{x-1} -1 =
\frac{x+1}{x-1} - \frac{x-1}{x-1} =
\frac{x+1-x-1}{x-1} =
\frac{0}{x-1} =
0

Uhh, what?[/spoiler]

[Anonymous No.5644855]

gtfo

[Anonymous No.5644857]

$\frac{x+1}{x-1} -1 = \frac{x+1}{x-1} - \frac{x-1}{x-1} = \frac{x+1-(x-1)}{x-1} = \frac{2}{x-1} = 0

[Anonymous No.5644861]

<span class="math">\frac{x+1}{x-1} -1 = \frac{x+1}{x-1} - \frac{x-1}{x-1} = \frac{x+1-(x-1)}{x-1} = \frac{2}{x-1}[/spoiler]

[Anonymous No.5644880]

>>5644861

Ooh. Thanks. :3

[Anonymous No.5644889]

\frac{x+1}{x-1} -1 = 0

\frac{x+1}{x-1} = 1
x+1 = x-1
+1 = -1
+1 - 1 = -1 - 1
0 = -2
\frac{0}{-2} = \frac{-2}{-2}
0 = 1
{\emptyset} = {\emptyset , {\emptyset}}
A = B
A \union B = C = A
However {\emptyset} \in C but {\emptyset} \notin A

[I'llPlayThatEcuation No.5646753]

>>5644855