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/sci/ - Science & Math


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5592764 No.5592764 [Reply] [Original]

A girl nds $1.05 in dimes, nickels and pennies. If there are 17 coins in all, how many
coins of each type can she have?
You should be able to solve this.

>> No.5592768

n_dime+n_nickel+n_penny= 17
n_dime*value_dime+n_nickel*value_nickel+n_penny*value_penny= 1.05

there are infinite solutions to this system, the thing is finding those that give you a natural number for n_dime, n_nickel and n_penny

>> No.5592770

>>5592768
if there is such solution, good.
If there isnt, it can't be solved unless you are chopping your coins

>> No.5592775

>>5592764
number of dime=D, Nickel=N and pennies are P... we also know that two nickles equals one dime

Now, P+D+N=17(*)

And we know that one penny is x=0,01, nickel=0,05 and the dime=0,10

Now we get:

0,01P+0,05N+0,2N=1,05
and we get 0,01P+0,25N=1,05.... also using you solve this by not being lazy like me and finishing it off.

>> No.5592774

13 nickels
4 dimes

>> No.5592781

>>5592775
and yeah it has infinite solutions, you get a function I think

>> No.5592832

>>5592781
>and yeah it has infinite solutions

not unless youre cutting coins in half

>> No.5592836

>>5592832
sorry, not infinite.. I'm kind of realizing this is more complex than I thought

>> No.5592850

>people on /sci/ don't even know what a basis is.
>/sci/ can't into modulation
Jesus Christ
4 dimes,13 nickels
>der are infinite solutions!
only in the reals, faggots
hint:
You should end up with two equations
(9/4)d+n=22
p=17-d-n
d(dimes) can only be equal to 0,4, and 8. Only one of these have a solution.

>> No.5592866

>>5592850
There are two solutions:
4 dimes, 13 nickels
and
8 dimes, 4 nickles, 5 pennies