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/sci/ - Science & Math

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File: 1.05 MB, 3264x1840, Engineering Problem 1.jpg [View same] [iqdb] [saucenao] [google]
5576843 No.5576843 [Reply] [Original]

Hey /sci/ I need some help with this problem!

I don't want the answer!

I would rather have instruction on how to go about completing these in the future.

I think I am on the right track, but I could be doing it completely wrong. Any advice would be helpful on where I need to go.

Thank you!

>> No.5576846
File: 928 KB, 3264x1840, Engineering work 1.jpg [View same] [iqdb] [saucenao] [google]
5576846

Here is all my work, I keep getting 16.66

>> No.5576865

>>5576846
try having the hypotenuse as 10

>> No.5576878

>>5576865

Sorry the work I have written down is wrong, I did use the hypotenuse as 10. I get the same thing 16.66

>> No.5576883

i just want to point out that this is a vector problem and not a "let's fuck around with right triangles" problem

your welcome

>> No.5576898

>>5576883

Are you sure? The professor said to draw a FBD of right triangles.

>> No.5576911

>>5576883
so
1) you are a scavenger, and you are butthurt
2) you somehow collect butthurt

>> No.5576915

>>5576878
> change the length of the sides of a right triangle
> get the same thing

>> No.5576937

>>5576915

I meant the drawing was different than the actual number I plugged in. Sorry if there was confusion.

>> No.5576996

Sum up the tensions in the x direction. Then you can find what the tensions would be equal to by having the greater tension equal to 10 (max tension).

Also the answer o got was 15.21

>> No.5577020

>>5576843
A bucket Weights mass?

>> No.5577030

>>5576843
You need to go into your physics book and look up how to break things into components. You are solving for a force which are the units of kilogram per merter•second squared AKA the Newton.
You need to use Newton's second Law, Fnet=ma. You know that the system is not moving so acceleration is going to be 0. That leaves you with Fnet=0. But you also know that there is a force of gravity down, which is F=mg. But wait, there is also two other forces, the string tension from each string. now set up Fnet=F1+F2+F3+...=0, and solve for whatever you are looking for. I think the fnet on the cables are the combined tensions in the y direction so you might have to break their forces into their y components.

>> No.5577034

>>5577030
And put units on all of your numbers to make sure you get the right units and so we know what the fuck you are writing.