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/sci/ - Science & Math

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5549225 No.5549225[DELETED]  [Reply] [Original]

Could you guys help me find the height of the chimney to the right?

>> No.5549232

It's h.

>> No.5549235

>>5549232
Thanks!

>> No.5549242

>>5549225
tan36°=h/x
tan23°=h/(50+x)
Solve for h.

>> No.5549243

Who the fuck wastes time measuring all these goddamn angles when a call to the builder will get you the damn height of the chimney.

Also, he chimney is not even necessarily h meters tall. it could start at the second floor making it (h-y) meters tall.

And why do you even need to know? Are you going to break into the house by jumping down the chimney? Only criminals need math because they use it to murder innocent people!!!

>> No.5549250

51.048

>> No.5549252

>>5549243
I know it's bullshit, but this is just a stupid school assignment... Hate doing shit like this, when I don't care about the problem

>> No.5549255

>>5549250
How?

>> No.5549262

>>5549225
You start of with the fact:
tan(23)*(50+x)=tan(36)*x
you calculate x
and then h is either of the two sides of the equation.

>> No.5549266

>>5549255
Take a set square, draw a scaled down version of the 50m, apply the angles and measure.

>> No.5549290

Apparently, i need to use either pythagora, cosinus or sinus relations

Do these solutions fill those requirements?

>> No.5549291
File: 3 KB, 180x130, 180px-LabeledTriangle.svg.png [View same] [iqdb] [saucenao] [google]
5549291

>>5549255
All angles in a triangle add up to 180 degrees

23 degrees and 180-36= 144 degrees for the shallow angle, and thus remaining 13 degrees for the sharp angle at the top.

http://en.wikipedia.org/wiki/Law_of_sines

Use the Law of sines to calculate the small hypothenuse, large hypothenuse and use pythagoras to calculate height.

>> No.5549293

>>5549291
But It's a right angle triangle?

>> No.5549294

>>5549291
Forgot the step, calculate x with law of sines along the way. But that speaks for itself I guess.

>> No.5549304

>>5549293

We don't know that from the information given. It's a math problem, you don't call it a right triangle just because it looks like one.

>> No.5549312

>>5549304
Aren't chimneys usually straight?

>> No.5549313

>>5549290
Dude, you just got the solution right here:
>>5549262
And here:
>>5549290
captcha : Watssa matter-with-you

>> No.5549318

>>5549312
That's how they get you at math tests, you see.

>> No.5549322

>>5549312
my chimney curves a little to the right.

>> No.5549326

Y = hypotenuse of the smaller right angle triangle
50/sin(180-23-[180-36] = y/sin23
50/sin13 = y/sin23
(50/sin13)*sin23 = y
Y = 86.8 (aprox)

86.8/Sin 90 (=1) = X/sin36
86.8*sin36 = X
X = 51 (aprox)

>> No.5549329

>>5549322
That's a Cheyronie.

>> No.5549332
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5549332

Step 1, look at the wiki for Law of sines and use it.

>> No.5549338

>>5549332
I don't understand the Law of sines...

>> No.5549344

>>5549338
Now i understand!!
God I'm an idiot

>> No.5549357
File: 90 KB, 1182x615, das.png [View same] [iqdb] [saucenao] [google]
5549357

Step 2 and last step,

Use law of sines again. Because you only know 1 side, the hypothenuse you calculated in step 1.

you don't even have to calculate x to reach it. you need to assume it's a right triangle in the right corner, or else this is unsolvable.

>> No.5549358

Wait a mo - let me get my ladders

>> No.5549364

>>5549357

I forgot to correct angle A but that's the right corner of course!

>> No.5549369

>/sci/ - jr. high math hw assistance

>> No.5549375

>>5549369

they need to start somewhere right?

>> No.5549383

>>5549375
You misspelled 'elsewhere'.

>> No.5549384

>>5549357
The wiki only shows examples where two sides are used, yet i only know the size of one of them

>> No.5549387

h/x=tan(36°)
h/(x+50)=tan(23°)

h=x*tan(36°)
h=(x+50)*tan(23°)

h=50/((tan(36°)/tan(23°)-1))*tan(36°)

h=51.048

>> No.5549394

>>5549384
You only need 1 side and all the angles to solve. Read again grasshopper.

>> No.5549405
File: 980 B, 252x42, db294be8057ef5a33ecc90a182f9bab0.png [View same] [iqdb] [saucenao] [google]
5549405

Only part you need in the entire exercise.

>> No.5549438

>>5549405
So c/sinC is 50/sin(13) ?

>> No.5549448

>>5549438
Yes, and you can use that principle to calculate all the other sides. But now i'm going to bed. Good luck.

>> No.5549457

>>5549448
Thanks stranger! You really helped me!
When you get out of /b/, you really get to see the true face of 4chan

>> No.5549459

>>5549457
You may call me Anonymous

>> No.5549520

>>5549357
I can prove it is a right triagle:

180 - 36 = 144
A = 144
C1 = 13
C1 is this >>5549332 C here

180 - 36 - 90 = 54
C2 - C1 = 54
C2 is this C >>5549332

180 - 23 - 90 = 67
C2 = 67

Once again:
C2 - C1 = 54
67 - 13 = 54

Correct?