/sci/ - Science & Math

[Anonymous No.5346914]

x = 1

Someone help me out here, i got an exam on this tomorrow.

[Anonymous No.5346923]

>>5346914
it's simple dude, first you square both sides, then you subtract 1 from both sides, then you subtract x^2 from both sides, then you take the square root and you see plainly that <span class="math">ix = \sqrt{-1}[/spoiler]. It can be simplified from there I think tho.

[Anonymous No.5346925]

What are you solving for?

What axioms are you supplied with or can you assume Peano arithmetic?

[Anonymous No.5346932]

>>5346923

Where do you get the 1 from?

[Anonymous No.5346937]

isn't that a linear equation with no slope? one that passes through 1 on the x axis?

[Anonymous No.5346944]

>>5346932

Not poster, but from there you can subtract both to the left side, then use defn of imaginary number to pull out an i. So, you have the product of i and x-1 is 0, so by some aiom I cba to look up right now, you'd get x=1 since i isn't 1 by defn.

Jesus, do some work yourself

[Anonymous No.5346947]

>>5346932
It is the successor of 0. :)

[Anonymous No.5346949]

>>5346914

Subtract 1 from both sides to get

(x-1) = 0

This is a linear equation with 1 as it's solution.

Therefore x = 1.

OK?

[Anonymous No.5346959]

>>5346949
no dude you've got to multiply both sides by (x-1) to get <span class="math">x^2-2x+1=0[/spoiler] then use the quadratic equation.

[Anonymous No.5346968]

>>5346959

OR if you just multiply both sides by x, then you can still use the quadratic equation but you uncover the previously lost solution x=0.

[Anonymous No.5346969]

>>5346949
So x-1=0
If x=y^2
(y+1)*(y-1)=0
So either y equals 1 or -1
Since y^2=x, x=1.
QED.

[Anonymous No.5346970]

>>5346968

x=1=0 ?

This is getting too complicated for me

[Anonymous No.5346973]

>>5346914

Make the substitution X=x+1 to give X=0

[Anonymous No.5346994]

i cant figure this shit out

[Anonymous No.5347006]

>>5346968
I'm trying to follow your train of thought here.
x-1=0
x(x-1)=0x
x^2-x=0
If, as >>5346969 says, y=square root of x
(x+y)*(x-y)=0
So either x=y or x=-y
The only number where x^2=x is 1.
QED.

Ooor x^2-x=0
x^2+0x-x=0
a=1
b=0
c=-1
[0+sqrt(0-4*1*-1)]/2 or [0-sqrt(0-4*1*-1)]/2
sqrt(0+4)/2 or [0-sqrt(0-4)]/2
sqrt(4)/2
2/2
x=1
or
(0-2i)/2
-2i/2
x=-i

[Anonymous No.5347007]

>>5347000
what is this, /ic/?

[Anonymous No.5347000]

>>5346994

I'd try using better handwriting and only one stroke per line?

[Anonymous No.5347009]

>>5347000
so close

[Anonymous No.5347011]

>>5347006
x=1 and -(sqrt(-1))
1=-i

[Anonymous No.5347016]

>>5347009

Don't do the foot on your 1.

>>5347006
Leave it as x(x-1)=0 then we have two solns, x-1=0, which >>5346969 showed how to solve or x=0, which speaks for itself imo

[Anonymous No.5347022]

>>5347016

[Anonymous No.5347024]

>>5347022

Leave off the hat too?

[Anonymous No.5347025]

>>5347016
there's a hidden cubic here you're missing, and that's when you multiply both sides by x-2 to get
<span class="math">x(x-1)(x-2) = 0[/spoiler] which shows you that 2 is also a solution.

[Anonymous No.5347033]

>>5347025

I'm sorry, I don't know how I missed that. Finals must be frying my brain.

[Anonymous No.5347035]

differentiate with respect to 1 to give,

0=1.

oh fuck, you're on your own...

[Anonymous No.5347038]

>>5347024
now we just need to figure out I

[Anonymous No.5347045]

>>5347038

Okay, try 1 like you were doing it before, but make the foot a separate stroke. Ie, do the hat and vertical line as one stroke, then lift and do the horizontal line independently.

[Anonymous No.5347048]

>>5346994
>>5347009
>>5347022
>>5347038
10/10

[Anonymous No.5347049]

>>5347038
> babby's first 1
wait until you're in graduate-level classes pleb

[Anonymous No.5347053]

>>5347045

[Anonymous No.5347059]

>>5347053

Make it a bigass hat, like it's offering shade to x and =

[Anonymous No.5347066]

No one has multiplied by (x +1) on both sides yet?

x = 1
(x - 1) = 0
(x - 1)(x + 1) = 0(x + 1)
x^2 - 1 = 0.

So x = - 1.

[Anonymous No.5347067]

>>5347059
i think im getting closer

[Anonymous No.5347068]

So x=1=0=2=-1=-i?

[Anonymous No.5347075]

>>5347066
so far x=1, -1, 0, and 2. Is it possible this is actually a quintic equation and we're missing a root???

[Anonymous No.5347078]

>>5346914
>x is hermitian
>x is an observable quantity
>x commutes with the hamiltonian
>you can construct simultaneous eigenstates of x and H
>you solved the problem
>you got the girl

[Anonymous No.5347073]

x = 1

So x + y = 1 when y = sin(pi).

Solved it, OP.

[Anonymous No.5347080]

>>5347067

Okay, maybe try adding some hearts?

[Anonymous No.5347083]

>>5347068
Multiply both sides by (x - phi)

(x - 1)(x - phi) = 0

So x = phi. It is amazing how much the golden ratio comes up isn't it? it?

[Anonymous No.5347085]

>>5347080

[Anonymous No.5347092]

>>5347085

Okay, I know what the problem is. x is so thankful for the shade that it wants to stick its penis in 1. So use the = as guidance there

[Anonymous No.5347095]

>>5347083
wow it really does come up everywhere!

[Anonymous No.5347098]

>>5347092

[Anonymous No.5347101]

>>5347098

Okay, then add phi watching on like a dirty whore and you should be good. I've got finals to study for, but you're welcome!

[Anonymous No.5347105]

This picture has never been more appropriate

[Anonymous No.5347111]

>>5347101
Sweet, thanks!