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/sci/ - Science & Math

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5264817 No.5264817 [Reply] [Original]

how do you solve analithictly stuff like this?

. stuff never seen before.

please make my angryness go away.

>> No.5264828

>>5264817
ever heard of logarithms broski

>> No.5264849

Not sure if troll...

>> No.5264865

Don't worry if you can't solve it, this is one of the great unsolved problems in mathematics.

>> No.5264868 [DELETED] 

>>5264817
The solution follows as a trivial corollary from my proof of the Riemann hypothesis.

>> No.5264936
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5264936

what the fuck man that question is so retardedi actually had to think about it, trying to figure out if what i am reading is actually what i am reading
7/10 gj.

>> No.5264971

OP, you suck. You must be in middle school, and even then, you'd still be a dumb middle schooler.

From what I can tell, because yo decided to use paint instead of a tool made to write this shit out, is 1/729 = (1/3)^x.

Take the natural log of both sides.

ln(1/729) = x*ln(1/3)

then divide

[ln(1/729)]/[ln(1/3)] = x

And there is the unsimplified answer.

Now, put that in a calculator and you'll have a decimal approximation of x.

>> No.5264992

>>5264971
don't need to make it that complicated
(1/729) = (1/3)^x
729 = 3^x
log3(729) = x

>> No.5264993

There's no need to use logs.

<span class="math"> \frac{1}{729} = \left(\frac{1}{3}\right)^6 = \left(\frac{1}{3}\right)^x \Leftrightarrow x = 6 [/spoiler]

>> No.5265018

>>5264971 Take the natural log of both sides.

Not OP

What is letting you know that this is what you need to do? I don't "get" logs yet.

>> No.5265028

Why is everyone saying, 'TAKE DA LOG XD?' This is a trivial problem which relates squares/roots, etc.

729 is a multiple of 3; specifically, it is 3^6. OP, just do this:

(1/729) = (1/3)^x
(729)^-1 = (3)^-x
(3)^-6 = (3)^-x

Hence, -6 = -x

Or, 6 = x.

There. Problem solved. None of this logarithmic business.

>> No.5265029

>>5264993
Yeah, someone else noticed it before I did. This post is correct, too.

Jesus. Some of you guys need to learn to become familiar with number patterns, or squares/cubes. Half of the time, these problems are based in that nonsense.

>> No.5265032

>>5265018
there's a logarithmic law about exponents stating that log(c^d) = d * log(c), allowing him to remove the x from the power

>> No.5265035

>>5265029
>find the answer by knowing the answer in advance.

>> No.5265070

>>5265035
There's a point in math where some things you should just have memorized.

I think knowing 3^6 = 729 is an extreme, but you should know the Rule of 9s and be able factor it out to "3x3x81" while sleeping.

>> No.5265071

>>5265035
>not knowing that 729 is 27^2