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/sci/ - Science & Math

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5105914 No.5105914 [Reply] [Original]

What does it mean when someone says the acceleration is .5g?

inb4 retard. Just answer the question please and I'll be on my way

>> No.5105918

self-bump

>> No.5105920 [DELETED] 

It is half of 4.81 m/s^2

>> No.5105921

1g is an acceleration of 9.80665 m/s^2
0.5g is an acceleration of 4.90333 m/s^2

>> No.5105923 [DELETED] 

>>5105920
Oh and forgot to mention they are wrong though
G is force not acceleration, but they mean that

>> No.5105924

Its the acceleration felt.
1g=9.81ms^-2, or earths gravity at sea level.
So basically 1g is felt when you jump.

>> No.5105925

>>5105921
thank you

>> No.5105926 [DELETED] 

>>5105923
fuck i mean vector acceleration, don't dink and post kids

>> No.5105927

it means that your mom is a pretty good lay.

Actually, acceleration due to gravity (g) is roughly 10 m/s/s. When someone says that "it feels like xG's," they are saying that the acceleration feels like some mutiple of G.

>> No.5105933

Relative to earth standard gravity, an acceleration of 4.9 m/s/s or so.

Now that that's answered, I have another question. they've redone the maths on the Alcubierre drive and have found that it's not only feasible, potentially easy, requiring a much smaller cost than was previously thought.

Assume, for the moment, that is true and the resultant drive works, allowing effective ftl travel.

What happens when one using these drives hits a speck of interstellar dust? Would the speed of the local space-time bubble determine the force of the impact, or the effective speed?

>> No.5105938

>>5105914
1 g is one time the acceleration any body experiences near the surface of the earth (~9.8 m/s²). It's used as a handy unit to compare certain acceleartions, mainly relative to humans, e.g. a jet pilot experiences 5g doing a loop. A high number of g can kill you.
It's calculated by F[G]/m[2]=(G*m[1][m2])/(r²m[2])

>> No.5105971

>>5105933
The spacecraft in the bubble doesn't experience any acceleration. So an impact wouldn't impart any force on the ship. It is said that any dust encountered would be trapped in the leading edge of the bubble and turned into radiation. Disposing of the built-up radiation from all the particles encountered during the journey may be a problem.

They didn't find that it was feasible or potentially easy, either. It's not. They found that instead of requiring Jupiter's mass equivalency in energy (totally impossible) it may only take on the order of 1000kg (could be possible in the distant future). Just making 1kg of antimatter is unthinkable today, and we have no way of storing it. Besides power supply there are probably issues no one has thought of yet that will throw a spanner in the cogs. Perhaps in the construction of the ring or how the field will be steered around.

>> No.5105974

Gravity is pulling down at 9.8m/s. 0.5g means acceleration is going 4.9m/s. Which means thats half the amount of accelerator needed to break away from gravity's pull. If its at 1g acceleration, the object in motion is free of gravity. I think this is right

>> No.5106000

>>5105933
Source plz

>> No.5106059

>>5105974
m/s/s bitch