/sci/ - Science & Math

File: 22 KB, 380x287, drugs.jpg [View same] [iqdb] [saucenao] [google]

Anonymous Sat May 26 21:29:03 2012 No.4721092 [Reply] [Original]

How would you find 2.353535353535...cont. without using a calculator?

>>	Anonymous Sat May 26 21:29:48 2012 No.4721094 *As a fraction

>>	Anonymous Sat May 26 21:32:32 2012 No.4721101 File: 42 KB, 240x240, op-1331172488932.jpg [View same] [iqdb] [saucenao] [google] By noticing the repeat length and seeing immediately that it is 2 35/99.

>>	Anonymous Sat May 26 21:36:32 2012 No.4721108 File: 24 KB, 204x250, read this.jpg [View same] [iqdb] [saucenao] [google] >>4721101 you will die a virign

>>	Anonymous Sat May 26 21:39:18 2012 No.4721116 File: 17 KB, 405x289, facepalm.jpg [View same] [iqdb] [saucenao] [google] >>4721101 moron

>>	Anonymous Sat May 26 21:42:03 2012 No.4721124 2+35/99 = X

>>	Anonymous Sat May 26 21:42:32 2012 No.4721126 >>4721116 you should really check and answer before you call it wrong.

>>	Anonymous Sat May 26 21:43:02 2012 No.4721131 >>4721126 im looking for a general method

>>	Anonymous Sat May 26 21:43:02 2012 No.4721132 >>4721126 an answer*

Anonymous Sat May 26 21:43:18 2012 No.4721128
File: 35 KB, 674x363, op-1301026258410.jpg [View same] [iqdb] [saucenao] [google]

>>4721116
What, is my math wrong? Or I could go with a longer repeat length of 4 for the fraction, and get 3535/9999. It just so happens that they are both muliples of 101 and I get (surprise!) 35/99.

>>	Anonymous Sat May 26 21:45:02 2012 No.4721134 ex . 1.37777777777777777777

>>	Anonymous Sat May 26 21:45:17 2012 No.4721136 >>4721131 Long division?

>>	Anonymous Sat May 26 21:45:33 2012 No.4721137 >>4721131 The repeitive part divided by that part's length amount of 9's. 2.1717171717..... 17 repeats over and over, 2 digits in length. 2 + 17/99

Anonymous Sat May 26 21:46:47 2012 No.4721139

>>4721131
That is general, you ass licking cock sucker OP. Find the repeat length, make that many nines, make a fraction. And that's even more general than the original question asked for.

Now if you want to know how to determine the repeat length without eyeballing it, then that would probably be NP hard to determine whether the number is even rational or not.

Anonymous Sat May 26 21:47:02 2012 No.4721140

>>4721137
(cont'd)

If you have a chunk before the repetition, multiply by an appropriate power of ten to make sure the decimal is only repetitive without junk numbers.

3.184747474747...

= 318.474747474........ divided by 100
= 318 + 47/99 divided by 100

>>	Anonymous Sat May 26 21:47:17 2012 No.4721141 >>4721128 protip: 3535/9999=35/99, you basically just said .5 might not be 1/2 because it could be 2/4

>>	Anonymous Sat May 26 21:47:47 2012 No.4721143 File: 73 KB, 300x301, 1274593113816.jpg [View same] [iqdb] [saucenao] [google] (1) 2.3535... = x (2) 235.3535... = 100x Subtract (1) from (2) = 233 = 99x x= 233/99 100x = 2 repeating digits 1000x = 3 repeating digits etc...

>>	Anonymous Sat May 26 21:49:48 2012 No.4721148 >>4721141 Um, did you read the part where I said they were both multiples of 101? You know, to maybe (finger quotes and Dr. Evil voice) "reduce" the fraction?

>>	Anonymous Sat May 26 21:49:48 2012 No.4721149 >>4721141 nb sorry thought you were op being potato

>>	Anonymous Sat May 26 21:50:02 2012 No.4721154 here, see the repeating number as a series. use the rule for geometric series that sn=a/1-r where a = 35/100 and r = 1/100 right since its essentially .35 +.0035+.000035+... you get (35/100)/(1-(1/100)) = 35/99 2+35/99 = 235/99

>>	Anonymous Sat May 26 21:53:18 2012 No.4721161 >>4721154 I think you mean 233/99

>>	Anonymous Sat May 26 21:53:47 2012 No.4721162 >>4721137 >>4721140 thx

>>	Anonymous Sat May 26 21:55:03 2012 No.4721165 here, see the repeating number as a series. use the rule for geometric series that sn=a/1-r where a = 35/100 and r = 1/100 right since its essentially .35 +.0035+.000035+... you get (35/100)/(1-(1/100)) = 35/99 2+35/99 = 233/99

>>	Anonymous Sat May 26 21:55:47 2012 No.4721169 >>4721161 yea

>>	Anonymous Sat May 26 21:57:03 2012 No.4721175 >>4721092 > How would you find 2.353535353535...cont. without using a calculator? You should start by looking under your bed. Numbers like to hide in dark, cool places and are attracted to the smell of sweaty cum-stained socks.

>>	Anonymous Sat May 26 21:58:32 2012 No.4721178 File: 486 KB, 300x316, 1337712967619.gif [View same] [iqdb] [saucenao] [google] >>4721165 >>4721165 >>4721165 thank you, this

Anonymous Sat May 26 21:59:33 2012 No.4721180

If possible you could rewrite the number as an infinite sum and then, provided you had memorized the formulas for solving that particular kind of sum, solve it as a fraction

for instance the # 2.353535 can be written as
2 + sum from 0 to infinity .35/10^(2n)

the sum from 0 to inf of C/10^(2n) is always 100C/99 so the answer is 2+35/99

>>	Anonymous Sat May 26 22:00:18 2012 No.4721181 >>4721180 see >>4721165

Advanced search
Text to find
Subject [?]Search by post subject. Leave empty for any.
Username [?]Search for user name. Leave empty for any user name.
Tripcode [?]Search for tripcode. Leave empty for any.
Email [?]Search by email. Leave empty for any.
Filename [?]Search by image filename. Leave empty for any.
From Date [?]Enter what date to start searching from. Format is YYYY-MM-DD
To Date [?]Enter what date to start searching until. Format is YYYY-MM-DD
Image hash
Search in	All Posts OPs Only
Deleted posts	Show all posts Show only deleted posts Only show non-deleted posts
Internal posts	Show all posts Show only internal posts Show only archived posts
Order	New posts first Old posts first
Capcode	All Posts Only by Users Only by Mods Only by Admins Only by Developers
Results	Posts Threads
Action	[ Simple ]