disproving math by use of calculus

[Anonymous No.4694988]

<span class="math">\frac{\partial{4}}{\partial{2}} = 0 [/spoiler] because <span class="math">4[/spoiler] is constant.

But <span class="math">\frac{\partial{4}}{\partial{2}} = \frac{\partial{2^2}}{\partial{2}} = 2\cdot 2^{2-1} = 4[/spoiler]

Therefore we have proved that <span class="math">0 = 4[/spoiler]

[EK !EKFnQG0UBo No.4694990]

[Anonymous No.4694992]

I can disprove it with simple algebra, pleb.
X=2X => X/X=2 => 1=2 Q.E.D.

[Anonymous No.4695001]

You can't differentiate with respect to a constant.

[Anonymous No.4695011]

>>4695001
>implying 2 is constant

[Anonymous No.4695013]

Only someone who has an absolute shitty foundation of calculus will be stumped by this kind of troll math.

I hope that most people learned calculus in the right way

[Anonymous No.4695017]

>>4695011

[Anonymous No.4695020]

>>4695011
It is.
x=2
dx=d(2)=0

The same troll maths it always was.

[It almost works, kinda No.4695021]

<span class="math">x^2=(x+x....+x)\;x\: times[/spoiler]
We now differentiate with respect to x.
<span class="math">2x=(1+1....+1)\;x\: times[/spoiler]
Therefore, <span class="math">2x=x[/spoiler] and <span class="math">2=1[/spoiler].

[Anonymous No.4695024]

<div class="math">\frac{\partial 4}{\partial 2} = \frac{4}{2} = 2</div>

Therefore 4 = 2 = 0.