/sci/ - Science & Math

[Anonymous No.4542365]

A man wanted to get into his work building, but he had forgotten his code. However, he did remember five clues. These are what those clues were:

The fifth number plus the third number equals fourteen.
The fourth number is one more than the second number.
The first number is one less than twice the second number.
The second number plus the third number equals ten.
The sum of all five numbers is 30.

I am not a maths student, but I thought I would be able to solve this problem. What is wrong with me? I keep getting 4C = 22

[Anonymous No.4542369]

abcde

c+e=14
d=b+1
a+1=2b
b+c=10
a+b+c+d+e=30

Elementary problem.

[Anonymous No.4542375]

So D = B - 1 is wrong thank you allow this thread to fade into the ether.

[resident /sci/ economist !!0CqB7P/574e No.4542390]

a = 7
b = 4
c = 6
d = 5
e = 8

Woo. Math is fun.

[resident /sci/ economist !!0CqB7P/574e No.4542399]

>>4542390

And just to elaboratw

A + B + C + D + E = 30
since C + E = 14

A + B + D + (C+E) = 30
A + B + D + 14 = 30
A + B + D = 16

2B = A + 1
B = .5A + .5

A + (.5A + .5) + D = 16
1.5A + D = 15.5

D = B + 1
D = (.5A +.5) + 1
1.5A + (.5A + 1.5) = 14
2A = 14
A = 7

7 + 1 = 2B
B = 4

C + 4 = 10
C = 6

D = 4 + 1
D = 5

E = 14 - 6
E = 8