/sci/ - Science & Math

[Anonymous No.4519589]

i need one of you chinky math motherfuckers to help me out wtf is 2+2

[Anonymous No.4519598]

10. What is base 4
every base is base 10
an infinite number of mathematicians walk into a bar (ouch) etc.

[Anonymous No.4519603]

what i dont get it?

[Anonymous No.4519609]

Come on man.
>an infinite number of mathematicians walk into a bar (ouch)
Get it? They walk INTO a bar.

[Anonymous No.4519613]

oh haha do you happen to be asian

[Anonymous No.4519620]

>>4519613
Indonesian.

[Anonymous No.4519626]

>>4519598

[Anonymous No.4519630]

here is a model theoretic proof for 1+1=2.
2+2 can be found and justified similarly.

[Anonymous No.4519640]

science is my best subject so ask a kid who won a national science contest anyhting

[Anonymous No.4519644]

>>4519640
>national science contest
>science
>math

[Anonymous No.4519775]

>>4519626
In what we call "base 4" for example, you get 1,2,3,10, and the 4th digit is 10. In base 2, 1,10. The 2nd digit is 10, not 2. In base 10, 1,2,3,4,5,6,7,8,9,10, the 10th digit is 10. Every base is base 10.

[Anonymous No.4521669]

8 _Kd

this is the highest math there is

good luck understand it
it's called feynman algebra

[Anonymous No.4521862]

>>4519630
you mean type-theoretic

[Anonymous No.4521867]

x = 2+2

exp(x) = exp(2+2)
exp(x) = exp(2)*exp(2)
exp(x) = 2exp(2)
log[exp(x)] = log[2exp(2)]
x = log(2*exp(2))


2 + 2 = log(2*exp(2))

QED

[Anonymous No.4521887]

Nigga, exp(x) != exp(2)*exp(2)

[Anonymous No.4521892]

wait nigga, very drunk right now, meant exp(2)*exp(2) != 2exp(2)

[Anonymous No.4521903]

<span class="math">2+2=\sum\limits_{n=0}^{3}1[/spoiler]
<span class="math">2+2=\sum\limits_{n=0}^{3}e^{0}[/spoiler]
we expand the exponential as <span class="math">e^{x}=\sum\limits_{n=0}\frac{x^{n}}{n!}[/spoiler]
so we have:
<span class="math">2+2=\sum\limits_{n=0}^{3}\frac{x_{0}^{n}}{n!}[/spoiler]
The terms in the sum vanish for <span class="math">n\neq 0[/spoiler] because only <span class="math">0^{0}=1[/spoiler] is non zero. So,
<span class="math">2+2=\frac{1}{0!}[/spoiler]

<span class="math">2+2=\frac{1}{2}=1[/spoiler]

as expected.

[Anonymous No.4521910]

<span class="math">2+2=\sum\limits_{n=0}^{3}1[/spoiler]
<span class="math">2+2=\sum\limits_{n=0}^{3}e^{0}[/spoiler]
we expand the exponential as <span class="math">e^{x}=\sum\limits_{n=0}\frac{x^{n}}{n!}[/spoiler]
so we have:
<span class="math">2+2=\sum\limits_{n=0}^{3}\frac{x_{0}^{n}}{n!}[/spoiler]
The terms in the sum vanish for <span class="math">n\neq 0[/spoiler] because only <span class="math">0^{0}=1[/spoiler] is non zero. So,
<span class="math">2+2=\frac{1}{0!}[/spoiler]

<span class="math">2+2=\frac{1}{1}=1[/spoiler]

as expected.

[Anonymous No.4522183]

>>4521892
>meant derp(2)*derp(2) != 2derp(2)
derp