[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math


View post   

File: 18 KB, 400x400, spintop..jpg [View same] [iqdb] [saucenao] [google]
4474704 No.4474704 [Reply] [Original]

I have a simple question for you, followed by an incredible revelation.

Do there exist different shaped lightwaves?

>> No.4474712

0/10

>> No.4474722

Nobody knows?

>> No.4474732

enjoy your ban

>> No.4474737

ban? Don't be ridiculous. I'm about to prove the theory of relativity wrong. Someone answer that question.

>> No.4474743

defined "shaped"

>> No.4474745

>>4474737
>I'm about to prove the theory of relativity wrong.
I doubt that this will happen on a 4chan board, but I am interested to see where this goes.

>> No.4474767

Shape. Some waves are longer than other waves, for example.

>> No.4474784

Nobody? It's not that hard a question.

>> No.4474813

>>4474784
>implying photons can be described in terms of spatial "shape"

>> No.4474817

>>4474767
Not really. Your concept of waves is pretty lacking, so I doubt any argument you give based of it will be worth considering.

>> No.4474822
File: 278 KB, 554x539, tripfags.png [View same] [iqdb] [saucenao] [google]
4474822

em radiation is just that, an oscillation of electric and magnetic fields. what do you mean, 'shape?'

>> No.4474829
File: 4 KB, 462x504, Visible_EM_modes.png [View same] [iqdb] [saucenao] [google]
4474829

well, each colour of light has a different wavelength if that's what you mean....

>I'm about to prove the theory of relativity wrong.
explain yourself

>> No.4474835
File: 16 KB, 320x320, laughing cartoon guy.jpg [View same] [iqdb] [saucenao] [google]
4474835

>about to prove relativity wrong

Be aware, OP, that everybody who has ever typed, written, or uttered this phrase has been laughably undereducated in the subject and obviously wrong.

Do go on, though.

>> No.4474879

No waves are differ in length? Check your facts. Why do you think they have a use the word "wavelength"?

>> No.4474884

they use*

>> No.4474888

wow what the hell,
No waves differ in length? Check your facts. Why do you think they use the word "wavelength"?
I mean

>> No.4474894

"well, each colour of light has a different wavelength if that's what you mean....

>I'm about to prove the theory of relativity wrong.
explain yourself"
Yes. Now what assumptions are made to come up with the wave equation?

>> No.4474897

The wave equation d²f(x,t)/dx²=(1/v²) d²f(x,t)/dt²

>> No.4474902

Maybe this will make it easier.

When does this function fill the wave equation:
f(x,t) = a*sin(kx-wt) + A*sin(Kx-Wt) ?
as opposed to just f(x,t)=a*sin(kx-wt), it doesn't always necessarily fill the requirements for the wave equation.

>> No.4474904
File: 83 KB, 920x1325, girls-920-13.jpg [View same] [iqdb] [saucenao] [google]
4474904

>>4474894
equations for light, and indeed the speed of light, can be derived from equations and constants from electricity and magnetism, no relativity needed

also, is this okay stuff to post on a work safe board?

>> No.4474906

So when DOES it fill the requirements? No need to point anything out mathematically, you can just explain it in a few words.

>> No.4474919

Fine. I'll do that.

We have a pulse that moves through time, conserving its shape. Just from this assumption it can be derived that:
d² f(x,t) / dx² = 1/v² * d² f(x,t) / dt²

Does anyone disagree?

>> No.4474928

>>4474904
That will be fine. please and thank you for image

>> No.4474927

What's a work safe board? :)

>> No.4474932

>>4474919
>conserving its shape

What do you mean by this?

>> No.4474933

>>4474927
They are the boards which have blue back grounds like this one and a few others (/sp/, /o/ etc) you cannot post porn/gruesome/ adult content images that are deemed offensive/illegal,

The boards with the orange/brown backgrounds are ok for posting adult content, but still not illegal content. (/b/, /soc/ etc)

They are in the rules if you havent seen them

>> No.4474941

"What do you mean by this?"
That the shape of the pulse remains the same.
a simple example: draw a graph of f(x)=a*sin(kx) then draw a graph of f(x) = a*sin(kx-2)
You'll notice that the latter looks the same but the position of the points are slightly different (they've moved two steps forward).

>> No.4474944

k*2 I mean :)

>> No.4474949

I'd suggest trying to get a decent understanding of differential equations before trying to think about this anymore.

>> No.4474955

Why do you say that? You didn't even point out any errors. Can't do that?

>> No.4474957

>>4474955
Your knowledge of the subject is bad enought that anything you say doesn't make any sense at all. Not even wrong.

>> No.4474962

You still didn't point out what. Can you give me an example and maybe I can explain what lacks in your understanding.

>> No.4474963

So, I was told that light has mass, small, but it is supposed to have a mass since it's a wavelength and shit, I'm not into Physics or whereever that would fall into.

I called bullshit, but couldn' back up my claim.

PS: I think we were talking about faster than light particles/atoms/tachyons and I said that nothing could go faster than light since light doesn't have any mass?

>> No.4474966

>>4474962
For one thing, you seem to be under the impression that every wave needs to have a specific phase and wavelength.

>> No.4474967

No. The speed of light is constant because it can be derived from Maxwell's equations that light fills the requirements for the wave equation and when certain conditions are met (we are in a vacuum), the speed of that wave is constant.
https://en.wikipedia.org/wiki/Electromagnetic_wave_equation

>> No.4474970

>>4474963
>I called bullshit, but couldn' back up my claim.

E = mc² is only true in the frame of reference where the particle is at rest. There is no such frame for light. The correct relationship is E² = (mc²)² + (cp)², which means

<div class="math">m^2 = \frac{E^2 - (cp)^2}{c^4}</div>

which is exactly zero for light.

>> No.4474976

"For one thing, you seem to be under the impression that every wave needs to have a specific phase and wavelength."

What makes you think I say that? I merely said that in order to come to the wave equation we need to assume that the shape of the wave remains the same.

>> No.4474981

>>4474976
>I merely said that in order to come to the wave equation we need to assume that the shape of the wave remains the same.

The word shape is meaningless.

>> No.4474982

Out of interest are you the same anonymous who claimed no waves differ from each other?

>> No.4474980

>>4474970

Many thanks.

>> No.4474985

Why is it meaningless, silly person?

>> No.4474987

>>4474985
Shape is not a mathematical property of a wave. Unless you are able to express your point with equations in a sensible way, anything you say is pointless.

>> No.4474990

Surely you can't be that silly. Read through my posts again before you say anything.

>> No.4474992

>>4474990
Your posts make no sense. You are too ignorant to even understand that you are not making sense. You have no knowledge of what it means to deal with solutions of a differential equations. Learn something and then come back.

>> No.4475031

>light has mass

But it has no rest mass because it never rests. You can use the following eqns to ascribe an energy-equivalent mass (m) to a photon with a rest mass (m0) of zero and a momentum of p:

E^2=m^2*c^4=m0^2*c^4+p^2*c^2

p_photon=E_photon/c=h/l=h*f/c

l=wavelength, f=frequency and h=quantum of action (Planck's constant)

>> No.4475038

>>4475031
Oh, /sci/, how can you still get things completely wrong when the correct answer has already been provided?

>> No.4475061

The dimwit aside, everyone probably understands what I'm talking about.
So, if we determine that the shape of the wave must remain the same, it must follow that lightwave shapes should remain the same as a function of time. This is how we come to the wave equation in the first place. It doesn't matter how we determine that shape, the most important part is that it's a function of x-coordinates and time. This is all good and well. Maxwell's equations truly do fill the wave equation perfectly.
However, if we take into account that the space is inflating, following the FRW-metric one can come to the conclusion that lightwaves stretch as a function of time. This would imply that light can not fill all the requirements for wave equations perfectly.

I'll conclude this rather unpleasant conversation by copying a link:
http://arxiv.org/abs/0908.0249

PDF file can be downloaded from the top-right corner.

>> No.4475067

>>4475061
>I have no idea what I'm talking about so I'll just string together a bunch of words to make people think I'm smart
>here, have this unpublished paper written by a biologist to prove I'm right

>> No.4475074

Boohoo sand in your pussy much? I would hate to be proven wrong, too.

>> No.4475100

The writers there probably came to a different theory but the emphasis is on "empirical evidence". also it's a pretty trusted source.

>> No.4475162

bump

>> No.4475283

No objections?

>> No.4475329

hmm that does sound pretty convincing..

>> No.4475381

So I take it the theory of relativity is now proven wrong?