[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math

View post   
File: 281 KB, 1101x618, 1271613219531.png [View same] [iqdb] [saucenao] [google]
4472192 No.4472192 [Reply] [Original]

Hydrochloric acid (36.5 g/mol) is sold as a concentrated aqueous solution. If the molarity of
commercial HCl is 12.0 M and its density is 1.18 g/mL, calculate the molality of the solution.

Apparently the answer is 16.2m
I keep getting 10.2m

12 mol / 1L
1L * (1000mL / 1 L) * (1.18g / 1mL) * (1kg / 1000g) = 1.18 kg

12 mol / 1.18 kg = 10.2m

where did i go wrong?

>> No.4472199

No homework threads on /sci/. If you can't handle elementary school math, it's time for you to drop out.

>> No.4472221

>>4472199
Hydrochloric acid (36.5 g/mol) is sold as a concentrated aqueous solution. If the molarity of
commercial HCl is 12.0 M and its density is 1.18 g/mL, calculate the molality of the solution.

Apparently the answer is 16.2m
I keep getting 10.2m

12 mol / 1L
1L * (1000mL / 1 L) * (1.18g / 1mL) * (1kg / 1000g) = 1.18 kg

12 mol / 1.18 kg = 10.2m

where did i go wrong?

>> No.4472242

>>4472221
All you need is multiplication and addition. If this is too hard for you, you're wrong in university.

>> No.4472249

>>4472242
Hydrochloric acid (36.5 g/mol) is sold as a concentrated aqueous solution. If the molarity of
commercial HCl is 12.0 M and its density is 1.18 g/mL, calculate the molality of the solution.

Apparently the answer is 16.2m
I keep getting 10.2m

12 mol / 1L
1L * (1000mL / 1 L) * (1.18g / 1mL) * (1kg / 1000g) = 1.18 kg

12 mol / 1.18 kg = 10.2m

where did i go wrong?