/sci/ - Science & Math

[Anonymous No.4262036]

Hey /sci/ I just need some help to derivate this
y=x^(2x)
I got to this:
y'=[2x^(2x)](1+lnx)
Is it correct?
Thanks in advance

[Anonymous No.4262044]

My favorite part was when derivate is a noun.

[Anonymous No.4262053]

yes.
in the future:
http://www.wolframalpha.com

[Aquila !!gAQL6Rry0wi No.4262073]

<div class="math">y=x^{2x}</div>
<div class="math">\ln(y)=\ln\left(x^{2x}\right)</div>
<div class="math">\ln(y)=2x\ln(x)</div>
<div class="math">\frac{d}{dx}\ln(y)=\frac{d}{dx}2x\ln(x)</div>
<div class="math">\frac{dy}{dx}y^{-1}=\left(2x\left(x^{-1}\right)\right)+(2\ln(x))</div>
<div class="math">\frac{dy}{dx}y^{-1}=2+2\ln(x)</div>
<div class="math">\frac{dy}{dx}=2y(1+\ln(x))</div>