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/sci/ - Science & Math

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4260382 No.4260382 [Reply] [Original]

It is correct to write
<span class="math">(a)^n[/spoiler]
instead of
<span class="math">\prod \limits_{m=0}^{n} a[/spoiler],
as long as m=0, right? If not, I might have found the problem that is keeping me from proving an otherwise not-so-hard equation.

>> No.4260387 [DELETED] 

what do you think?

>> No.4260391

>>4260387
I think it's more or less another way to describe exponentiation, since it's (0*a) * ... * (n*a), as far as I know. If not - I am new to it, sorry.

>> No.4260399

no

>> No.4260467

Try this.
What is the answer if m=0 and n=1?

>> No.4260474

>>4260467
It's 0. Anything multiplied by 0 is 0.

>> No.4260483

<span class="math">\prod \limits_{m=0}^{n-1} a = a^n[/spoiler]

>> No.4260490

>>4260474
Yes, anything multiplied by 0 is 0. No, your answer is not necessarily 0 because why do you think you are necessarily multiplying by 0?

>> No.4260500

>>4260474
Where do you think 0 gets in there? You are only multiplying a*a*a*...
m=0, m=1, m=2, ...

>>4260391
(0*a) * ... * (n*a)
would be
<span class="math">\prod_{m=0}^{n} m a[/spoiler]
which is something else (and equal to zero)

>> No.4260502

>>4260490
Are you trolling? You set m=0.

>> No.4260517

>>4260502
Yes. I set m=0. But m is not in your product. You have a*a*a*a*a*a*...*a
Please explain to me how m gets in there because I am quite curious.

>> No.4260525

>>4260517
Can't you read, faggot? There is an M in the product.
I'm OP coming here for help and you guys know even less math than me.

>> No.4260548

>>4260525
Uh, no. You don't know more than me.

Let's say you have m=0 and n=2.
First step: m=0.
The part to the right of the net product sign is a. Thus your working product is a.
Second step: m=1.
The part to the right of the net product sign is a. Thus your working product is a*a.
Third step: m=2.
The part to the right of the net product sign is a. Thus your working product is a*a*a.
You've now reached m=n, so you are done. Your answer is a*a*a.

>> No.4260552
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4260552

>>4260548

>> No.4260555

>>4260525
Worded less eloquently, you think you're doing the operation this anon wrote up:
>>4260500
but that's not what you wrote.

>> No.4260588

<span class="math">\prod \limits_{m=0}^{n} a = a_0 * a_1 ... a_n = a^{n+1}[/spoiler]

>> No.4260605

The iterator isn't even in your term.