/sci/ - Science & Math

[Anonymous No.4138853]

How would I find the weight of this I BEAM cross section made of steel (density = 7860 kg/m^3)
per unit length in N/M and LBf/ft

[Anonymous No.4138860]

>>4138853
units are in mm on the drawing

[Anonymous No.4138872]

You got to integrate the moment of inertia to get volume. From there you multiply it by density to get weight.

[Anonymous No.4138885]

1.Convert units
2.Figure out the area
4.????
5.Profit!

This is a simple question and it shouldn't be hard. Just look at the units of density, look at the answer units i.e. N/m and LBf/ft then figure out how to combine the area and density and gravity to get your answer

[Anonymous No.4138905]

how the fuck do i get volume on a 2d cross section?

[Anonymous No.4138914]

>>4138905

Ignore
>>4138872
he doesnt know what he's talking about

You dont need volume, just area, since you need your answers in unit per length

[Anonymous No.4138919]

>>4138853
density per unit length

[Anonymous No.4138924]

Ok so the combined area is 35m^2

P=m/v, volume is in cubed units, where do i get my extra dimension at

[Anonymous No.4138936]

Heres the problem out of the book

[Anonymous No.4138952]

>>4138924
I hope you are not trolling me
I'll do this in meters

Volume = m^3
area = m^2
density = kg/m^3


kg/(m*m*m) multiply by area which is m*m
Two m's cancel and you are left with kg/m

N = (kg*m)/s^2

so kg/m times gravity m/s^2

= kg/m * m/s^2 (this time dont cancel the m's)
so you get
(kg*m/s^2)/m which is N/m

[Anonymous No.4139094]

Can someone go through the work quick?