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Anonymous Wed Dec 7 05:17:44 2011 No.4110894 [Reply] [Original]

Anyone here good with predicate logic? Because I am not and I need help solving this proof.

1. (x)(~Rx v Nx)
2. ~(Ǝx)Nx v (Ǝy)(z)Szy ∴ ~(Ǝx)Rx v (z)(Ǝy)Szy

If someone just tells me where to begin I could get it from there, I just have no idea where to start. Using Demorgan's Law on the disjunctions has gotten me nowhere.

>>	GL !Bgpe2HycPk Wed Dec 7 05:22:16 2011 No.4110904 >1. (x)(~Rx v Nx) What do you mean by (x)? Is is ∀x?

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