what now sci? [spoiler]yeah, it's homework[/spoilersdontworkonsci]

File: 12 KB, 603x390, prove.png [View same] [iqdb] [saucenao] [google]

Anonymous Sat Oct 29 17:20:25 2011 No.3971344 [Reply] [Original]

what now sci?
[spoiler]yeah, it's homework[/spoilersdontworkonsci]

>>	Anonymous Sat Oct 29 17:23:25 2011 No.3971363 File: 56 KB, 708x915, 1305827149423.gif [View same] [iqdb] [saucenao] [google] >>3971344 */sci/

>>	Anonymous Sat Oct 29 17:26:25 2011 No.3971373 If an element is in AnB, then it is in A. So if we were to try to remove an element in C that was not in A from AnB, nothing would happen. So it's just (AnB)\C, which should be easier for you.

>>	Anonymous Sat Oct 29 17:30:25 2011 No.3971387 You that guy from openstudy?

>>	Anonymous Sat Oct 29 17:32:25 2011 No.3971397 >>3971373 ok... thanks >>3971387 yea.

Anonymous Sat Oct 29 17:38:43 2011 No.3971426 [DELETED]

x \in A \cap (B \backslash C) [/spoiler]
\Leftrightarrow x \in A[/spoiler] and x \in (B \backslash C) [/spoiler]
 \Leftrightarrow x\in B [/spoiler] and x \notin C [/spoiler]
 \Leftrightarrow x \in A \cap B [/spoiler] and x \notin A \cap C [/spoiler]
\Leftrightarrow x \notin (A \cap B) \backslash (A \cap C) [/spoiler]

Anonymous Sat Oct 29 17:41:25 2011 No.3971437

x \in A \cap (B \backslash C) [/spoiler]
\Leftrightarrow x \in A[/spoiler] and x \in (B \backslash C) [/spoiler]
 \Leftrightarrow x\in B [/spoiler] and x \notin C [/spoiler]
 \Leftrightarrow x \in A \cap B [/spoiler] and x \notin A \cap C [/spoiler]
\Leftrightarrow x \in (A \cap B) \backslash (A \cap C) [/spoiler]

Minor typo fixed

>>	Anonymous Sat Oct 29 17:42:25 2011 No.3971438 File: 65 KB, 818x1058, 1305827470941.gif [View same] [iqdb] [saucenao] [google] >>3971426 thanks

>>	Anonymous Sat Oct 29 17:43:25 2011 No.3971443 >>3971437 again, thanks

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