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/sci/ - Science & Math

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3943599 No.3943599 [Reply] [Original]

It is easy to show that a^n + b^n = c^n for any integer value n greater than 2. The proof is left as an exercise to the reader.

>> No.3943622

OP is a cheeky cunt.

>> No.3943920

Bump.

>> No.3943927

Hai Rudin.

>> No.3943928

I can show it for n=3 easy

>> No.3943935

(1)^3 + (2)^3 = (3)^3

wat

>> No.3943942

>>3943928
wait no I lied, n=3k is fairly hard. n=4k is easy

>> No.3943991

c = (a^n + b^n) ^ (1/n)
If you don't clarify your hypothesis it's legit.

>> No.3944011

>>3943991
Or a=b=c=0. But OP's statement doesn't even mean a thing, as there are no quantifiers on a, b and c. It's like asking to show that a=b.

>> No.3944158
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3944158

>This proof is so trivial we leave it to the reader.

>> No.3944178

At least have the decency to quote the theorem correctly.

>> No.3944185

>>3943599

Sure thing Fermat!