/sci/ - Science & Math

[Anonymous No.3857702]

In C++ how do I check if an int has a certain number in it? For example, checking if a number like 49 has a 9 in it.

[Anonymous No.3857706]

divisibility tables and modulus operator
do your own homework

[Anonymous No.3857710]

Design a gui using Visual Basic. Zoom and enhance the int, and rotate it by 75 degree by Z-axis for maximum effect.

[Anonymous No.3857720]

>>3857706
I know about that but it doesn't help for a number like 17 that isn't evenly divisible by 9 but has a 7 in it.

[Anonymous No.3857729]

>>3857706
I know about that but it doesn't help for a number like 19 that isn't evenly divisible by 9 but has a 9 in it.

[Anonymous No.3857738]

>>3857702
Run it through a bayesian filter.

[Anonymous No.3857742]

convert to string
search

[Anonymous No.3857750]

>>3857710
Fucking moron. You have to use the reflections before rotate 75 degree.

[Handstandard !eZurQiPamQ No.3857754]

>Convert to string
>check each character
^_^

[Anonymous No.3857771]

>>3857750
No, you need to print.line, then run a typographic analysis.

Also, make sure you check 180 degrees, otherwise you may confuse a 9 for a 6.

[Marion Bartoli is my Waifu No.3857772]

[Anonymous No.3857838]

Here (because why not. I'm bored)

bool numFound(int numToBeFound,int numString){
int magnitude=1;

if(numString/10==0){
if(numToBeFound==numString){
return true;
}else{
return false;
}
}

while((numString/magnitude)!=0){
if((((numString%(magnitude*10))-(numString%magnitude))/magnitude)==numToBeFound){
return true;
}

magnitude*=10;
}
return false
}

[Anonymous No.3857843]

>>3857838
I haven't thrown that by a compiler, by the way, so I can't guarantee it works, but it should.

Let me know the results.

[Anonymous No.3858940]

>>3857729
You misunderstand. You don't divide by 9, you divide by 10 (and look at the remainder).

If (x%10 == 9), then the last digit of the decimal representation is a 9. Similarly, if ((x/10)%10 == 9), then the next-to-last digit of the decimal representation is a 9.