/sci/ - Science & Math

[Anonymous No.3848345]

Proposition for you

Proposition: .99999... = 1
(That is .9 repeating infinity)
Proof:
let x = .99999...
10x = 9.9999...
10x - x = 9.99999... - .99999...
9x = 9
x = 1

Tell me I'm wrong if you can...

[Anonymous No.3848350]

You're not wrong. This is mathematically correct.

[Anonymous No.3848355]

[Marion Bartoli is my Waifu No.3848357]

> you can't travel at the speed of light
> only a fraction of it, 0.999...
> 0.999... = 1
> you can travel at the speed of light

[Anonymous No.3848368]

>>3848357
No. Wrong.

[Anonymous No.3848372]

Good job OP, you showed us something we already know.

[Anonymous No.3848379]

>>3848357
in b4 neutrinothread

[Anonymous No.3848385]

3*⅓=3*0.333...=1=0.999...

[Anonymous No.3848389]

I've never really gotten the appeal to intuition one where you get them to agree that 0.333... = 1/3 and go from there.

If they can accept 0.333... = 1/3 why are they even confused about 0.999... to begin with?? Isn't the confusion usually based on an inability to accept non-terminating decimals in the first place?

[Anonymous No.3848396]

>>3848389
Personal experience seems to suggest that this method is indeed ineffective at convincing people. What happens if they end up trying to work backwards (because they still don't want to accept that 0.999... = 1) and they conclude that 0.333... != 1/3

[Anonymous No.3848401]

>>3848396
>What happens, *is they end up

[Marion Bartoli is my Waifu No.3848403]

>>3848396
This is my experience as well. They assert that 0.333... isn't <span class="math">\frac{1}{3}[/spoiler].

[Anonymous No.3848420]

>>3848345
>>3848345

Nobody is saying you're wrong.

[Anonymous No.3848444]

GUYS, WAIT

What about...

the

0.000........... .......1 ?

incomplete 1 =/= complete 1

[Anonymous No.3848459]

.99999... keeps going forever. Which means you never reach the end. If you never reach the end, you can't finish calculating it. Thus, you can never finish proving it is = 1.

[Anonymous No.3848461]

It's right, but not very rigorous

let x = .99999...
10x = 9.9999...
10x - x = 9.99999... - .99999...
>Using 0.999... to multiply and subtract is a little dubious. You're not exactly sure what 0.999... actually IS. What you did was mathematically correct but it raises some suspicion from very strict people because you're using the object in question as a definite number.

Instead:
x = 0.999... = 9 (1/10 + 1/100 +...)
x + 9 = 9(1/(10^0) + 1/10 + 1/100 +...) = 9/(1 - (1/10)) = 10

(x + 9) - 9 = 10 - 9 = 1

>You make no new assumptions because you DO NOT directly add 9 + 0.999... = 9.999..., you only keep it as a variable. In order to get your 0.999... into 9.999..., you break it into a series so you can convince the hard ass, strict people that you're not making "new" assumptions with your object in question. The series also allows you to write it as a new, long ago confirmed number "10".

[Anonymous No.3848474]

>>3848444

It doesn't exist and you can't troll while posting a trollface image you inelegant insect.