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/sci/ - Science & Math

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File: 208 KB, 450x625, 93cd98d3a46faa15d604259d54ddd5e3_7246023.jpg [View same] [iqdb] [saucenao] [google]
[ERROR] No.3781020 [Reply] [Original]

You know how people at CERN get particles to hit other particles at really high speeds and they sometimes create other particles that only appear for a fraction of a second?
How is it possible for them to know that they made something for a split second inside a monster tube like that? How do they detect it?
Cause high speed filming microscopes aimed at the exact right spot seems improbable.
Also, how do they get these effin MICRO particles to hit each other directly on in such a thick tube?

>> No.3781041

>>3781020

It's because Alice has an Atlas, that's how it's done.

>> No.3781044

LHC has 5 GARGANTUAN computers on it.

It has thousands of custom-made sensors designed to take images that get analyzed.

>Also, how do they get these effin MICRO particles to hit each other directly on in such a thick tube?

Magnets.

>> No.3781057
File: 242 KB, 650x650, 1316459840535.jpg [View same] [iqdb] [saucenao] [google]
[ERROR]

>>3781020
MAGIC

>> No.3781068

multitude of detectors. also, it seems you dont know how microscopes work.

>> No.3781074

>>3781044
Oh okay. That works.

>> No.3781086
File: 97 KB, 620x617, cern_1540945i[1].jpg [View same] [iqdb] [saucenao] [google]
[ERROR]

>>3781020
As far as detection goes

The particles may only exist for a fraction of a second, but because of their high velocity they travel far enough to collide with material in the detectors.

Pic related. Except that picture has likely been cleaned up. When large numbers of particles are collided (such as gold ions at Brookhaven Lab) there are thousands of tracks. By analyzing the trajectory of the tracks (which are affected by electromagnetic fields) charge, mass, and spin can be inferred and particles can be identified.

The particles are collimated in a beam via magnets. It starts off with a large radius beam, and the magnets gradually accelerate and narrow the beam width.