/sci/ - Science & Math

[Anonymous No.3762814]

Hey guys, sorry for coming here with school shit, but I need help understanding this problem.

When 2.50g of a zinc strip were placed in a AgNO3 solution, silver metal formed on the surface of the strip. After some time had passed, the strip was removed from the solution, dried, and weighed. If the mass of the strip was 3.37g, calculate the mass of Ag and Zn metals present.

Any help?

[& !!tSqR6hj9NpI No.3762819]

Do percent mass calculations, find the ratio, apply to the end result.

[& !!tSqR6hj9NpI No.3762839]

Wait, reading further, it says silver forms ON the strip. It doesn't actually say anything about the zinc strip being used in the reaction. So it could be one of two things:

1) single replacement (somehow) forming a zinc-silver alloy
2) single replacement resulting in silver plated ZnNO3 (Cant remember charges, my apologies)
3) silver plated zinc, via a catalyst reaction.


In case 1 and 3, it's final mass - initial to find the weight of the silver, and you already know the mass of the zinc

In case 2, you use percent mass.

[Anonymous No.3762840]

Zn(s) + 2AgNO₃(aq) ⇋ Zn(NO₃)₂(aq) + 2Ag(s)

[Homework Helper No.3762848]

1. Write the Lagrangian
2. Do a Fourier Transform
3. Put your answer into the Heaviside function
4. Integrate it over the real line

There's your answer, OP.

[Anonymous No.3762910]

One Zn gets replaced by two Ag. The atomic weights are 65 and 108. So the increase is 216 - 65 = 151.

(3.37 g - 2.50 g) / 151 g/mol = 5.76 mmol of Zn

Mass Zn = 2.50 - (0.00576 mol * 65 g/mol) = 2.13 g

Mass Ag = 1.24 g