so here I am calculating this shit: f(1)=2*(1)^3+8*(1)^2+2*(1)-12 the answer is 0. That means that x-1 is a factor in f(x), right? why the fuck does (2x^3+8x^2+2x-12):(x-1) equal =2x^2+6x-4 then -8/x-1 Can anyone explain me this or point out where I did wrong?

File: 34 KB, 393x450, 1312983894783.jpg [View same] [iqdb] [saucenao] [google]
[ERROR]

Anonymous Thu Sep 15 14:48:36 2011 No.3742365 [Reply] [Original]

so here I am calculating this shit:

f(1)=2*(1)^3+8*(1)^2+2*(1)-12

the answer is 0.

That means that x-1 is a factor in f(x), right?

why the fuck does (2x^3+8x^2+2x-12):(x-1) equal =2x^2+6x-4 then -8/x-1

Can anyone explain me this or point out where I did wrong?

>>	Anonymous Thu Sep 15 14:50:36 2011 No.3742379 then -8/x-1 wut that's the part that is confusing the fuck out of me.

>>	Anonymous Thu Sep 15 14:53:36 2011 No.3742391 anyone?

>>	Anonymous Thu Sep 15 14:56:36 2011 No.3742406 2 x^3 + 8 x^2 + 2 x - 12 = 2 (x - 1) (2 + x) (3 + x)

>>	Failure !KYRLEGE8T6 Thu Sep 15 14:56:36 2011 No.3742409 >>3742365 You divided wrong, the answer is 2x^2 +10x + 12

>>	Anonymous Thu Sep 15 14:56:36 2011 No.3742412 >>3742409 >>3742406 my bad. sorry.

Advanced search
Text to find
Subject [?]Search by post subject. Leave empty for any.
Username [?]Search for user name. Leave empty for any user name.
Tripcode [?]Search for tripcode. Leave empty for any.
Email [?]Search by email. Leave empty for any.
Filename [?]Search by image filename. Leave empty for any.
From Date [?]Enter what date to start searching from. Format is YYYY-MM-DD
To Date [?]Enter what date to start searching until. Format is YYYY-MM-DD
Image hash
Search in	All Posts OPs Only
Deleted posts	Show all posts Show only deleted posts Only show non-deleted posts
Internal posts	Show all posts Show only internal posts Show only archived posts
Order	New posts first Old posts first
Capcode	All Posts Only by Users Only by Mods Only by Admins Only by Developers
Results	Posts Threads
Action	[ Simple ]

/sci/ - Science & Math