/sci/ - Science & Math

[Anonymous No.3646537]

question:

For the reaction
?C6H6 + ?O2 → ?CO2 + ?H2O
40.8 grams of C6H6 are allowed to react with 111.8 grams of O2. How much CO2 will be produced by this reaction?

[Anonymous No.3646548]

>>3646537
balance the equation.
give the numbers.
and perhaps someone will do it for you.

[Anonymous No.3646562]

bump

[Anonymous No.3646563]

>>3646562
faggot

[Anonymous No.3646568]

>>3646548
will do, sorry

[Anonymous No.3646574]

>>3646537
That's fucking easy.
go do it yourself.

[Anonymous No.3646596]

>>3646568
2C6H6 +15O2 -> 6H2O +12CO2

You use the magical periodic table to add up the elements and get:
C6H6 = 78.11 g/mol
O2 = 15.9 g/mol

Now you figure out which one is fucking up the equation by running out:

111.8/15.9 = 7.03144654 mole of O2
40.8/78.11 = 0.522340289 C6H6

.5/2 = 1/4
7/15 = 7/15
7/15>1/4

C6H6 is the limiting reactant.
use the equation with 0.522340289 moles of C6H6 and you get your answer.

also, stop being so fucking stupid.

[Anonymous No.3646598]

12C6H6 + 15O2 = 12CO2 +6H2O

>>3646568
wouldn't be asking if I knew

[Anonymous No.3646624]

is it 138.g with sig figs?

[Anonymous No.3646644]

>>3646537
Fuck you, OP. Go do your own bloody homework.

[Anonymous No.3646656]

plz

[Anonymous No.3646658]

>>3646537

[Anonymous No.3646672]

Stan, do your own damn homework

[Anonymous No.3646682]

how's high school OP

[Anonymous No.3646704]

balance the equation
run stoichiometry for each reactant
whichever makes less product is the limiting and is the accurate amount of product

now gtfo

[Anonymous No.3646990]

ingangsexamen geneeskunde?

I FEEL YOU, maar als ge dit niet kunt zult ge waarschijnlijk falen

[Anonymous No.3647821]

Veel succes, ge zult het nodig hebben.