/sci/ - Science & Math

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Anonymous Mon Aug 8 02:41:59 2011 No.3530288 [Reply] [Original]

1=(-1)(-1)
1=√(1)
Substitute:
1=√([-1][-1])
Distribution Law:
1=√(-1)*√(-1)
√(-1)=i
1=i*i
1=-1!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Where did I go wrong? Did I just prove that the distribution law doesn't work in all cases?

>>	Anonymous Mon Aug 8 02:50:59 2011 No.3530306 yes math made a mistake

>>	Anonymous Mon Aug 8 02:51:59 2011 No.3530311 >>3530288 No, your mistake is on line 4, sqrt(ab) =/ sqrt(a)sqrt(b) in all cases

>>	Anonymous Mon Aug 8 02:52:59 2011 No.3530317 1=√(1) false statment. √(1)= 1 or -1

>>	Anonymous Mon Aug 8 02:52:59 2011 No.3530321 File: 73 KB, 500x500, Cereal Man.jpg [View same] [iqdb] [saucenao] [google] >>3530288 how does i math?

>>	Anonymous Mon Aug 8 02:55:59 2011 No.3530328 File: 25 KB, 400x423, math_problem.png [View same] [iqdb] [saucenao] [google]

>>	Anonymous Mon Aug 8 02:58:59 2011 No.3530338 File: 33 KB, 640x480, fry.jpg [View same] [iqdb] [saucenao] [google] >>3530328 OP here. Division by zero.

>>	Anonymous Mon Aug 8 03:00:59 2011 No.3530342 >>3530338 >Implying you can't divide by zero 0/0 = 1

>>	Anonymous Mon Aug 8 03:03:59 2011 No.3530350 So I guess you could just call line 2 wrong for assuming positive. Then the distribution law is saved. Thank you.

>>	Anonymous Mon Aug 8 03:04:59 2011 No.3530353 OP here. >>3530342 Or 2 or pi.

>>	Anonymous Mon Aug 8 03:04:59 2011 No.3530355 File: 41 KB, 599x314, djhsjsrjkkj.jpg [View same] [iqdb] [saucenao] [google] >>3530342 implying you can.

>>	Anonymous Mon Aug 8 03:08:59 2011 No.3530374 File: 93 KB, 584x323, dfhfghjdf.jpg [View same] [iqdb] [saucenao] [google] >>3530342 nope.jpg

>>	Time to invade Chad !!yrsvUUPIY4s Mon Aug 8 03:12:59 2011 No.3530389 >>3530342 lolno Ok then You have 0 apples. Put the 0 apples into 0 bags. You now have 1 apple, and 1 bag? No. it doesn't work like that.

>>	Anonymous Mon Aug 8 03:13:59 2011 No.3530395 >>3530389 0^0 = 1 0/0 = 1 Have fun mulling that one over

>>	Anonymous Mon Aug 8 03:17:59 2011 No.3530412 File: 28 KB, 386x412, Copy of 1288022767486.jpg [View same] [iqdb] [saucenao] [google]

>>	Anonymous Mon Aug 8 03:19:59 2011 No.3530417 File: 61 KB, 360x202, hfdshfdj.jpg [View same] [iqdb] [saucenao] [google] >>3530395 >0^0=1 nope 0^0=0/0=undefined

Anonymous Mon Aug 8 03:20:59 2011 No.3530421

>>3530395
anything divided by zero is negative or positive infinity. as x gets larger in 1/x, the answer becomes smaller - since there are an infinite amount of numbers the answer is so big when you finally input zero

anything to the power of zero is 1 because x^a/x^a = x^(a-a) = x^(0)
but x^a/x^a = 1

>>	Anonymous Mon Aug 8 03:20:59 2011 No.3530423 0/0 is infinity

>>	Anonymous Mon Aug 8 03:22:42 2011 No.3530435 >>3530317 I seriously hope this bullshit is a troll by now. The real square root only takes positive values so 1^(1/2) = 1.

>>	Anonymous Mon Aug 8 03:22:59 2011 No.3530433 >>3530417 0^0 is defined to be 1.

>>	Anonymous Mon Aug 8 03:24:59 2011 No.3530448 >>3530342 >>3530395 >>3530423 >>3530433 NOPENOPENOPENOPE

Arshroom !!rRZtBJE6V2d Mon Aug 8 03:27:59 2011 No.3530463

Okay. Most of you that I've seen are just plain wrong about something. But... on topic:
√(1)=±1
√(-1(-1))=√(-1)*√(-1)=i*i=-1
√(-1(-1))=√(1)=±1
And also: order of operations. Parentheses come before exponents, and a square root is really just an exponent of 1/2.

>>	Anonymous Mon Aug 8 03:28:59 2011 No.3530466 >>3530448 http://en.wikipedia.org/wiki/Empty_product http://en.wikipedia.org/wiki/Exponentiation#Zero_to_the_zero_power >2011 >not knowing 0^0

>>	Anonymous Mon Aug 8 03:29:59 2011 No.3530469 File: 19 KB, 346x300, confus.jpg [View same] [iqdb] [saucenao] [google] >>3530433 0^0=0^1*0^-1=0/0=undefined http://www.wolframalpha.com/input/?i=0^0 >>3530421 >anything to the power of zero is 1 except for 0^0

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