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/sci/ - Science & Math

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3378963 No.3378963 [Reply] [Original]

differentiate log(log(log(x))) without a shitstorm.

>> No.3378966

dlog(log(log(x)))/dy = 0

>> No.3378970

1/log(log(x))

>> No.3378978
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3378978

Page 2. Just leave away the "+1".

>> No.3378980

sci can't do ANYTHING without a shitstorm

>> No.3378987

Are you a mathematician, physicist, or computer scientist?

>> No.3379001

>>3378966
>dlog(log(log(x)))/dy = 0
this

>> No.3379002

>>3378987
No.

>> No.3379008

>>3379001
Except that's wrong.

dy/dy = 1

>> No.3379011

>>3379008
Haha oh wow.

>> No.3379024

1/(ln(ln(x))*ln(x)*x)

What am I missing...

>> No.3379025

>>3379008
i don't even...

>> No.3379036

What?

Say y = f(x) = x
dy/dx = dx/dx = 1

Say x = f(y) = y
dx/dy = dy/dy = 1

What?

>> No.3379041

The log log log x is treated as a constant in respect to y because it wasn't explicitly said that y was equal to it? Is that why?

Instead of laughing at the dy/dy = 1 comment, you could try to explain WHY you're laughing.

>> No.3379120

>>3379008
except THAT'S wrong...

z=log(log(log(x)))

dz/dy=0

>> No.3379148

>>3378963
>sci cant
>differentiate blah blah

so true i cried a tear

>> No.3379168

1/(xlnx(x)lnlnx)

>> No.3379246

>>3379041
FFFFFFFFFFFFFFF you're a clueless wanker.

y not depending on x is your dumbass assumption.

in general it doesn't. the correct answer for df/dy, even if f is in terms of x alone, is df/dx*dy/dx.

OP was correct. the problem with /sci/ is not stupidity. the problem with /sci/ is stupidity which considers itself genius.

>> No.3379261

>>3379246
*df/dx*dx/dy
hur dur chain rule hur

>> No.3379282 [DELETED] 

sigh... I'll just leave this here
<span class="math">
\frac{dx}{dy}[log(log(log(x)))]=\frac{1}{xlog(10)log(x)log(\frac{log(x)}{log(10)})}
[/spoiler]

>> No.3379291 [DELETED] 

>>3379282
shit...
<span class="math">\frac{d}{dx}[/spoiler]
fix'd

>> No.3379313

wow, I'm full of fail today... ok, THIS time, I think I've got it:

<span class="math">
\frac{d}{dx}[log(log(log(x)))]=\frac{1}{xln(10)ln(x)ln(\frac{ln(x)}{ln(10)})}
[/spoiler]