/sci/ - Science & Math

[Anonymous No.3202930]

How would splashes look like with different gravities?

[Anonymous No.3202932]

>>3202930
Different

[Anonymous No.3202936]

Would the water splash to higher heights or lower heights when the gravity is increased?

(assuming the splash is caused by an object with a constant mass from a constant height)

[Anonymous No.3202939]

>>3202936
*DROPPED from a constant height

[EK !EKFQOBUFnQ No.3202940]

>>3202936
At lower gravity, the splash would reach higher heights.

[Anonymous No.3202945]

>>3202940
despite the fact that the force that causes the splash (mg) is lower?

[Fury No.3202966]

>>3202945

If you actually think about, realize all materials will have equally as low weight in relation to the same gravity.

[EK !EKFQOBUFnQ No.3202970]

>>3202966
so the splash will be the same?
i realise 'mg' will be lower, but when the water is thrown upwards by the splash, there is less gravity pulling it down, so i figured it would go higher.

[Anonymous No.3202976]

Let me be more specific with my question

A tank is filled with water and a ball is dropped from a certain height into the tank. This experiment is done in multiple planets with varying gravities. How would the splash look like in each planet?

(The fact that the water will be more condensed due to higher gravity also needs to be noticed)

[Anonymous No.3203002]

>>3202945
Go throw something at a wall, note how there is more force than gravity there? Now imagine doing that but at water.

[Anonymous No.3203006]

>>3202976
>The fact that the water will be more condensed due to higher gravity also needs to be noticed

What? The density has nothing to do with the value of g.

Still, I think the answer is that the splash will be bigger (i.e. the droplets will reach higher and the splash radious will be wider), at least if we're working in a vacuum. The ball's intial kinetic energy is an upper bound for the water droplets' maximum potential energy. So, if the droplets' size (and hence mass) doesn't change, then the droplets will reach higher (and farther away for the droplets that are projected at an angle, hence the larger splash radius). At least if we assume that the distribution of droplet sizes is the same for different values of the acceleration of gravity.

[EK !EKFQOBUFnQ No.3203009]

>>3203002
depends how hard you throw it...

OP is talking about dropping an object, therefore gravity is the only force that will be forming the splash. and hgravity is the only force determining how high the splash reaches.
considering conservation of energy, PE = mgH
so i think the splash will reach the same height on each of the different planets.

[Anonymous No.3203020]

>>3203006
Wait, you said "drop". That means that the initial potential energy changes, and so the kinetic energy of the ball when it hits the water also changes.

So, scratch that: >>3203006 (which contains the misunderstanding that the kinetic energy for the ball is constant). It seems to me that all else being constant (read: distribution of droplet sizes and hence masses is unaffected by g), the shape of the splash is the same, with its height proportional to the height from which the ball was dropped. So, I say the splash would be the same (the droplets would move faster or slower, though).

[Anonymous No.3203029]

splashing is an aftermath of collision...of course it will vary...

[Anonymous No.3203031]

Fluidmechanics: I've searched everywhere on the internet and I still have no idea. Can someone help me with it please? Oh, and this ain't my homework.

Specifically the Engineering Bernoulli Equation
thanks

[Anonymous No.3203036]

>>3203031
Fuc I'm retarded, why did I post this in a thread?

[Anonymous No.3203048]

>>3203036
...and I can't even spell 'fuck' correctly.

I think I'll just an hero over here in this corner...

[Anonymous No.3203070]

I very much doubt that the drops will stay the same

I dont know how to explain my self here but I think that in low gravity water molecules will hold each other much more strongly than in high gravity

[Anonymous No.3203079]

>>3203070
That's what's been bothering me, too. I'm fairly confident that if the drops don't change, then neither will the splash.

But the drops sizes are affected by surface tension, not gravity (there is some gravitational attraction between the molecules of a drop, of course, but it's laugably small). I think that, even if surface tension is affected by a change in g, the change is negligible. I'm not sure, though.

[Anonymous No.3203156]

>>3202940

>At lower gravity, the splash would reach higher heights.

AHAHAHAHHAHAHAHAHHAHAHAHAHAHAHAHHAHAHAHAHAHAHAHHAHAHAHAHHAHAHAHAHAHAHAHAHAHHAHAHAHAHAHHAHAHAHAHAHAHA
HHAHAHAHAHAHAHAHAHHAHAHAHAHAHHAHAHAHAHAHAHHAAHHAHAHAHAHAHHAHAHAHAHAHAHHAHAHAHAHAHAHHAHAHAHAHAHAHHAAH
AHAHAHAHAHHAHAHAHAHHAHAHAHAHAHAHAHAHAHHAHAHAHAHAHAHAHAHHAAHHAHAHAHAHAHHAHAHAHAHAHAHAHHAHAHAHAHAHHAHA
HAHAHAHAHHAHAHAHAHAHAHAHAHAHHAHAHAHAHAHAHAHAHAHAHAHAHHAAHHAHAHAHAHAHAHAHAHAHAHAHHAHAHAHHAHAHAHAHAHAH
AHAHAHAHAHAHAHHAHAHAHAHAHAHAHA

[EK !EKFQOBUFnQ No.3203168]

>>3203156
shut it!
if the same force is applied then i am right.
i just didnt consider that mgH would be lower as well if the gravity is lower.

[Anonymous No.3203174]

>>3203168

>id the same force is applied then I am right

AHAHAHAHHAHAHAHHAHAHAHAHHAHAHHAHAHAHHAHAHAHAHHAHAHAHHAHAHAHAHHAHAHAHAHAHAHAHHAAH

[EK !EKFQOBUFnQ No.3203177]

>>3203174
*if

and yeh.

[Anonymous No.3203184]

>>3203177

Oh lawdy you're the king of all idiots.

If the same force was applied then there wasn't a change in gravity.

lrn2basic physics

[Anonymous No.3203187]

>>3203184
>implying you couldnt give something more speed so more force overall is applied
>9.8x10=4.9x20
>hurr

[Anonymous No.3203191]

>>3203156
>>3203174
oh shit. You sir, are retarded

[Anonymous No.3203192]

>>3203168
weight is a force that is affected by gravity

[Anonymous No.3203194]

>>3203187

>(assuming the splash is caused by an object with a constant mass [dropped] from a constant height)

The only change that will occur is gravity, which is a force that causes things to accelerate. The acceleration due to gravity on earth is 9.8 m/s a second.

If the mass is the same and the "speed" is the same then the gravity didn't change, and neither will the force (lol the force).

But seriously, full retard

>>3203191

you too...

[Anonymous No.3203199]

>>3202936
Assuming a constant mass, lower gravity => less weight => less transfer of energy => less splash?

[Anonymous No.3203200]

>>3203194
I cant believe it. What are doing in /sci/ ?

[Anonymous No.3203203]

>>3203200

[Anonymous No.3203208]

>>3203194
>>3203203
samefaggin like a true amateur

[Anonymous No.3203210]

>>3203208

What is there a one post per thread rule...?

Either massive newfaggotry is afoot or I'm being trolled hard.

[Anonymous No.3203211]

>>3203208
And one guy that loves rubbing shit all over his body.

[Anonymous No.3203213]

ITT: high scoolers, that dont know anything about liquids.

[Anonymous No.3203219]

>>3203194
>>3203184
>>3203006

so much FAIL in this thread. How old are you?

[Anonymous No.3203220]

>>3203219

[Anonymous No.3203225]

ITT: underage physics

If you want to perform a thought experiment, do it correctly.

The splash depends on the shape, mass and velocity of the object as it hits the surface. The shape and mass do not change. The velocity would if you dropped the object from the same height, but let's assume that the object has been thrown at the surface in such a way that it has the same velocity when it hits the surface.

What does gravity affect during a splash? It doesn't change the surface tension because that's an independent property of the liquid. Pressure depends on gravity though. It's proportional to gravity and some power of the height beneath the surface, depending on whether or not the liquid is compressible. When the object hits the surface, it will still have the force of gravity acting on it, and it will also have the reaction force of the pressure against it's surface. The first depends linearly on gravity while the second may depend on a higher power of gravity. Generally though, liquids can be considered as incompressible fluids so the pressure will vary linearly. Even if it doesn't, it will be essentially linear in most cases for a short height beneath the surface.

So, the initial effects of the collision should be the same if the forces involved are all scaled linearly, i.e. they all remain proportional.

Because the surface tension remains the same, the beads that form and get ejected upwards should also have the same shape.

The amount of energy that they have will probably be different because the object still falls into the surface during the collision, which adds the energy of gravity over that distance (mgh).

After that, the ejected beads will follow nearly parabolic paths that depend on gravity, so larger g will cause the beads to fall back to the surface is shorter arcs, and vice versa.

[Anonymous No.3203228]

>>3203213
OP here
I match that description

[Anonymous No.3203243]

>>3203213

In this post: High schooler who wants to feel superior by pointing out others lack of expertise in an arcane subject, while simultaneously ignoring his own inability.

[Anonymous No.3203924]

I would say the splash is the same every time. As long as it is done in a vacuum, that is.

What many are failing to realize is that although the force applied by the ball changes, so does the weight of the water.

[Anonymous No.3206602]

gravities different with like look splashes would how